How to do a logical OR operation for integer comparison in shell scripting?

Question

I am trying to do a simple condition check, but it doesn't seem to work.

If $# is equal to 0 or is greater than 1 then say hello.

I have tried the following syntax with no success:

if [ "$#" == 0 -o "$#" > 1 ] ; then  echo "hello" fi  if [ "$#" == 0 ] || [ "$#" > 1 ] ; then  echo "hello" fi 

Answer 1

This should work:

#!/bin/bash  if [ "$#" -eq 0 ] || [ "$#" -gt 1 ] ; then     echo "hello" fi 

I'm not sure if this is different in other shells but if you wish to use <, >, you need to put them inside double parenthesis like so:

if (("$#" > 1))  ... 

Answer 2

This code works for me:

#!/bin/sh  argc=$# echo $argc if [ $argc -eq 0 -o $argc -eq 1 ]; then   echo "foo" else   echo "bar" fi 

I don't think sh supports "==". Use "=" to compare strings and -eq to compare ints.

man test 

for more details.