How to zero pad a sequence of integers in bash so that all have the same width?

Question

I need to loop some values,

for i in $(seq $first $last) do     does something here done 

For $first and $last, i need it to be of fixed length 5. So if the input is 1, i need to add zeros in front such that it becomes 00001. It loops till 99999 for example, but the length has to be 5.

E.g.: 00002, 00042, 00212, 012312 and so forth.

Any idea on how i can do that?

Answer 1

In your specific case though it's probably easiest to use the -f flag to seq to get it to format the numbers as it outputs the list. For example:

for i in $(seq -f "%05g" 10 15) do   echo $i done 

will produce the following output:

00010 00011 00012 00013 00014 00015 

More generally, bash has printf as a built-in so you can pad output with zeroes as follows:

$ i=99 $ printf "%05d\n" $i 00099 

You can use the -v flag to store the output in another variable:

$ i=99 $ printf -v j "%05d" $i $ echo $j 00099 

Notice that printf supports a slightly different format to seq so you need to use %05d instead of %05g.