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I want to execute a long running command in Bash, and both capture its exit status, and tee its output.
So I do this:
command | tee out.txt ST=$? The problem is that the variable ST captures the exit status of tee and not of command. How can I solve this?
Note that command is long running and redirecting the output to a file to view it later is not a good solution for me.
497
To check the exit code we can simply print the $? special variable in bash. This variable will print the exit code of the last run command.
A pipe is created and the commands on the left ( #part3 ) and right ( #part2 ) are executed. exit $xs is also the last command of the pipe and that means the string from stdin will be the exit status of the entire construct. A subshell is created with file descriptor 3 redirected to stdout.
There are many methods to quit the bash script, i.e., quit while writing a bash script, while execution, or at run time. One of the many known methods to exit a bash script while writing is the simple shortcut key, i.e., “Ctrl+X”. While at run time, you can exit the code using “Ctrl+Z”.
You can simply do a echo $? after executing the command/bash which will output the exit code of the program. Every command returns an exit status (sometimes referred to as a return status or exit code).
There is an internal Bash variable called $PIPESTATUS; it’s an array that holds the exit status of each command in your last foreground pipeline of commands.
<command> | tee out.txt ; test ${PIPESTATUS[0]} -eq 0 Or another alternative which also works with other shells (like zsh) would be to enable pipefail:
set -o pipefail ... The first option does not work with zsh due to a little bit different syntax.
153
Dumb solution: Connecting them through a named pipe (mkfifo). Then the command can be run second.
mkfifo pipe tee out.txt < pipe & command > pipe echo $? If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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