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I have a script that automates a process that needs access to a password protected system. The system is accessed via a command-line program that accepts the user password as an argument.
I would like to prompt the user to type in their password, assign it to a shell variable, and then use that variable to construct the command line of the accessing program (which will of course produce stream output that I will process).
I am a reasonably competent shell programmer in Bourne/Bash, but I don't know how to accept the user input without having it echo to the terminal (or maybe having it echoed using '*' characters).
Can anyone help with this?
243
#!/bin/bash echo "Enter Username : " # read username and echo username in terminal read username echo "Enter Password : " # password is read in silent mode i.e. it will # show nothing instead of password. read -s password echo echo "Your password is read in silent mode."
$@ refers to all of a shell script's command-line arguments. $1 , $2 , etc., refer to the first command-line argument, the second command-line argument, etc. Place variables in quotes if the values might have spaces in them.
$0 is the name of the script itself (script.sh) $1 is the first argument (filename1) $2 is the second argument (dir1) $9 is the ninth argument.
Here is another way to do it:
#!/bin/bash # Read Password echo -n Password: read -s password echo # Run Command echo $password The read -s will turn off echo for you. Just replace the echo on the last line with the command you want to run.
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A POSIX compliant answer. Notice the use of /bin/sh instead of /bin/bash. (It does work with bash, but it does not require bash.)
#!/bin/sh stty -echo printf "Password: " read PASSWORD stty echo printf "\n" If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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