Expansion of variables inside single quotes in a command in Bash

Question

I want to run a command from a bash script which has single quotes and some other commands inside the single quotes and a variable.

e.g. repo forall -c '....$variable'

In this format, $ is escaped and the variable is not expanded.

I tried the following variations but they were rejected:

repo forall -c '...."$variable" '  repo forall -c " '....$variable' "  " repo forall -c '....$variable' "  repo forall -c "'" ....$variable "'" 

If I substitute the value in place of the variable the command is executed just fine.

Please tell me where am I going wrong.

Answer 1

Inside single quotes everything is preserved literally, without exception.

That means you have to close the quotes, insert something, and then re-enter again.

'before'"$variable"'after' 'before'"'"'after' 'before'\''after' 

Word concatenation is simply done by juxtaposition. As you can verify, each of the above lines is a single word to the shell. Quotes (single or double quotes, depending on the situation) don't isolate words. They are only used to disable interpretation of various special characters, like whitespace, $, ;... For a good tutorial on quoting see Mark Reed's answer. Also relevant: Which characters need to be escaped in bash?

Do not concatenate strings interpreted by a shell

You should absolutely avoid building shell commands by concatenating variables. This is a bad idea similar to concatenation of SQL fragments (SQL injection!).

Usually it is possible to have placeholders in the command, and to supply the command together with variables so that the callee can receive them from the invocation arguments list.

For example, the following is very unsafe. DON'T DO THIS

script="echo \"Argument 1 is: $myvar\"" /bin/sh -c "$script" 

If the contents of $myvar is untrusted, here is an exploit:

myvar='foo"; echo "you were hacked' 

Instead of the above invocation, use positional arguments. The following invocation is better -- it's not exploitable:

script='echo "arg 1 is: $1"' /bin/sh -c "$script" -- "$myvar" 

Note the use of single ticks in the assignment to script, which means that it's taken literally, without variable expansion or any other form of interpretation.