How do you get the length of a string stored in a variable and assign that to another variable?
myvar="some string" echo ${#myvar} # 11
How do you set another variable to the output 11
?
Another way to count the length of a string is to use `expr` command with length keyword. The following commands will assign a value to the variable, $string, store the length value to the variable, $len and print the value of $len. Output: The following output will appear after running the above command.
$1 means an input argument and -z means non-defined or empty. You're testing whether an input argument to the script was defined when running the script.
A regular expression matching sign, the =~ operator, is used to identify regular expressions. Perl has a similar operator for regular expression corresponding, which stimulated this operator.
To get the length of a string stored in a variable, say:
myvar="some string" size=${#myvar}
To confirm it was properly saved, echo
it:
$ echo "$size" 11
In addition to fedorqui's correct answer, I would like to show the difference between string length and byte length:
myvar='Généralités' chrlen=${#myvar} oLang=$LANG oLcAll=$LC_ALL LANG=C LC_ALL=C bytlen=${#myvar} LANG=$oLang LC_ALL=$oLcAll printf "%s is %d char len, but %d bytes len.\n" "${myvar}" $chrlen $bytlen
will render:
Généralités is 11 char len, but 14 bytes len.
you could even have a look at stored chars:
myvar='Généralités' chrlen=${#myvar} oLang=$LANG oLcAll=$LC_ALL LANG=C LC_ALL=C bytlen=${#myvar} printf -v myreal "%q" "$myvar" LANG=$oLang LC_ALL=$oLcAll printf "%s has %d chars, %d bytes: (%s).\n" "${myvar}" $chrlen $bytlen "$myreal"
will answer:
Généralités has 11 chars, 14 bytes: ($'G\303\251n\303\251ralit\303\251s').
Nota: According to Isabell Cowan's comment, I've added setting to $LC_ALL
along with $LANG
.
Argument work same as regular variables
showStrLen() { local bytlen sreal oLang=$LANG oLcAll=$LC_ALL LANG=C LC_ALL=C bytlen=${#1} printf -v sreal %q "$1" LANG=$oLang LC_ALL=$oLcAll printf "String '%s' is %d bytes, but %d chars len: %s.\n" "$1" $bytlen ${#1} "$sreal" }
will work as
showStrLen théorème String 'théorème' is 10 bytes, but 8 chars len: $'th\303\251or\303\250me'
printf
correction tool:If you:
for string in Généralités Language Théorème Février "Left: ←" "Yin Yang ☯";do printf " - %-14s is %2d char length\n" "'$string'" ${#string} done - 'Généralités' is 11 char length - 'Language' is 8 char length - 'Théorème' is 8 char length - 'Février' is 7 char length - 'Left: ←' is 7 char length - 'Yin Yang ☯' is 10 char length
Not really pretty output!
For this, here is a little function:
strU8DiffLen() { local charlen=${#1} LANG=C LC_ALL=C return $(( ${#1} - charlen )) }
or written in one line:
strU8DiffLen() { local chLen=${#1} LANG=C LC_ALL=C;return $((${#1}-chLen));}
Then now:
for string in Généralités Language Théorème Février "Left: ←" "Yin Yang ☯";do strU8DiffLen "$string" printf " - %-$((14+$?))s is %2d chars length, but uses %2d bytes\n" \ "'$string'" ${#string} $((${#string}+$?)) done - 'Généralités' is 11 chars length, but uses 14 bytes - 'Language' is 8 chars length, but uses 8 bytes - 'Théorème' is 8 chars length, but uses 10 bytes - 'Février' is 7 chars length, but uses 8 bytes - 'Left: ←' is 7 chars length, but uses 9 bytes - 'Yin Yang ☯' is 10 chars length, but uses 12 bytes
But there left some strange UTF-8 behaviour, like double-spaced chars, zero spaced chars, reverse deplacement and other that could not be as simple...
Have a look at diffU8test.sh or diffU8test.sh.txt for more limitations.
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