I have this architechture/topology in Verilog:
How can I access the internal reg IntReg
, that isn't a input/output in IntModule
, in SystemVerilog?
always @(posedge clk) begin
$display ("[Time %0t ps] IntReg value = %x", $time, DUT.IntModule.IntReg);
end
Can I use bind? How?
You don't need to use bind
:
module DUT;
bit clk;
initial begin
repeat (5) begin
#5 clk = 0;
#5 clk = 1;
end
end
always @(posedge clk) begin
$display ("[Time %0t ps] IntReg value = %x", $time, DUT.IntModule.IntReg);
end
IntModule IntModule ();
endmodule
module IntModule;
reg IntReg = 1;
endmodule
Output:
[Time 10 ps] IntReg value = 1
[Time 20 ps] IntReg value = 1
[Time 30 ps] IntReg value = 1
[Time 40 ps] IntReg value = 1
[Time 50 ps] IntReg value = 1
Yes, you can use interface
with bind
:
// Interface
interface my_if(
input IntReg
);
endinterface: my_if
// Interface bind
bind intModule my_if my_if0(
.IntReg(IntReg)
);
Then access the register like this:
virtual my_if _if = top.DUT.IntModule.my_if0;
$display ("[Time %0t ps] IntReg value = %x",
$time, _if.IntReg);
Complete example with sim results on EDA Playground: http://www.edaplayground.com/s/4/115
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