Find lines from a file which are not present in another file [duplicate]

Question

The command you have to use is not diff but comm

comm -23 a.txt b.txt

By default, comm outputs 3 columns: left-only, right-only, both. The -1, -2 and -3 switches suppress these columns.

So, -23 hides the right-only and both columns, showing the lines that appear only in the first (left) file.

If you want to find lines that appear in both, you can use -12, which hides the left-only and right-only columns, leaving you with just the both column.

The simple answer did not work for me because I didn't realize comm matches line for line, so duplicate lines in one file will be printed as not-existing in the other. For example, if file1 contained:

Alex
Bill
Fred

And file2 contained:

Alex
Bill
Bill
Bill
Fred

Then comm -13 file1 file2 would output:

Bill
Bill

In my case, I wanted to know only that every string in file2 existed in file1, regardless of how many times that line occurred in each file.

Solution 1: use the -u (unique) flag to sort:

comm -13 <(sort -u file1) <(sort -u file2)

Solution 2: (the first "working" answer I found) from unix.stackexchange:

fgrep -v -f file1 file2

Note that if file2 contains duplicate lines that don't exist at all in file1, fgrep will output each of the duplicate lines. Also note that my totally non-scientific tests on a single laptop for a single (fairly large) dataset showed Solution 1 (using comm) to be almost 5 times faster than Solution 2 (using fgrep).

I am not sure why it has been said diff should not be used. I would use it to compare the two files and then output only lines that are in the left file but not in right one. Such lines are flagged by diff with < so it suffices to grep that symbol at the beginning of the line

diff a.txt b.txt  | grep \^\<

In the case the files wouldn't be sorted yet, you can use:

comm -23 <(sort a.txt) <(sort b.txt)