Multiplication on command line terminal

Question

Yes, you can use bash's built-in Arithmetic Expansion $(( )) to do some simple maths

$ echo "$((5 * 5))"
25

Check the Shell Arithmetic section in the Bash Reference Manual for a complete list of operators.

For sake of completeness, as other pointed out, if you need arbitrary precision, bc or dc would be better.

For more advanced and precise math consider using bc(1).

echo "3 * 2.19" | bc -l 
6.57

Internal Methods

Bash supports arithmetic expansion with $(( expression )). For example:

$ echo $(( 5 * 5 ))
25

External Methods

A number of utilities provide arithmetic, including bc and expr.

$ echo '5 * 5' | /usr/bin/bc
25

$ /usr/bin/expr 5 \* 5
25

The classical solution is:

 expr 5 \* 5

expr will only work with integer operands. Another nice option is:

 echo 5 5\*p | dc

dc can be made to work with non-integer operands.

A simple shell function (no sed needed) should do the trick of interpreting '5X5'

$ function calc { bc -l <<< ${@//[xX]/*}; };
$ calc 5X5
25
$ calc 5x5
25
$ calc '5*5'
25

I use this function which uses bc and thus supports floating point calculations:

c () { 
    local a
    (( $# > 0 )) && a="$@" || read -r -p "calc: " a
    bc -l <<< "$a"
}

Example:

$ c '5*5'
25
$ c 5/5
1.00000000000000000000
$ c 3.4/7.9
.43037974683544303797

Bash's arithmetic expansion doesn't support floats (but Korn shell and zsh do).

Example:

$ ksh -c 'echo "$((3.0 / 4))"'
0.75