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Removing the first n characters To remove the first n characters of a string, we can use the parameter expansion syntax ${str: position} in the Bash shell.
To delete a line, we'll use the sed “d” command. Note that you have to declare which line to delete. Otherwise, sed will delete all the lines.
Use cut. Eg. to strip the first 4 characters of each line (i.e. start on the 5th char):
tail -f logfile | grep org.springframework | cut -c 5-
sed 's/^.\{5\}//' logfile
and you replace 5 by the number you want...it should do the trick...
EDIT
if for each line
sed 's/^.\{5\}//g' logfile
You can use cut:
cut -c N- file.txt > new_file.txt
-c: characters
file.txt: input file
new_file.txt: output file
N-: Characters from N to end to be cut and output to the new file.
Can also have other args like: 'N' , 'N-M', '-M' meaning nth character, nth to mth character, first to mth character respectively.
This will perform the operation to each line of the input file.
tail -f logfile | grep org.springframework | cut -c 900-
would remove the first 900 characters
cut uses 900- to show the 900th character to the end of the line
however when I pipe all of this through grep I don't get anything
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