"find: paths must precede expression:" How do I specify a recursive search that also finds files in the current directory?

Question

Try putting it in quotes -- you're running into the shell's wildcard expansion, so what you're acually passing to find will look like:

find . -name bobtest.c cattest.c snowtest.c

...causing the syntax error. So try this instead:

find . -name '*test.c'

Note the single quotes around your file expression -- these will stop the shell (bash) expanding your wildcards.

What's happening is that the shell is expanding "*test.c" into a list of files. Try escaping the asterisk as:

find . -name \*test.c

Try putting it in quotes:

find . -name '*test.c'

From find manual:

NON-BUGS         

   Operator precedence surprises
   The command find . -name afile -o -name bfile -print will never print
   afile because this is actually equivalent to find . -name afile -o \(
   -name bfile -a -print \).  Remember that the precedence of -a is
   higher than that of -o and when there is no operator specified
   between tests, -a is assumed.

   “paths must precede expression” error message
   $ find . -name *.c -print
   find: paths must precede expression
   Usage: find [-H] [-L] [-P] [-Olevel] [-D ... [path...] [expression]

   This happens because *.c has been expanded by the shell resulting in
   find actually receiving a command line like this:
   find . -name frcode.c locate.c word_io.c -print
   That command is of course not going to work.  Instead of doing things
   this way, you should enclose the pattern in quotes or escape the
   wildcard:
   $ find . -name '*.c' -print
   $ find . -name \*.c -print

I see this question is already answered. I just want to share what worked for me. I was missing a space between ( and -name. So the correct way of chosen a files with excluding some of them would be like below;

find . -name 'my-file-*' -type f -not \( -name 'my-file-1.2.0.jar' -or -name 'my-file.jar' \)