T-SQL: Opposite to string concatenation - how to split string into multiple records [duplicate]
The STRING_SPLIT() function is a table-valued function that splits a string into a table that consists of rows of substrings based on a specified separator. In this syntax: input_string is a character-based expression that evaluates to a string of NVARCHAR , VARCHAR , NCHAR , or CHAR .
The Solution: Use STRING_SPLIT( ) DECLARE @categories VARCHAR(MAX) = 'value1,value2,value3'; Then you can use the STRING_SPLIT() function to turn those values into a recordset/array. Once it's in that format, you can use it in your IN clause as criteria.
There are a wide varieties of solutions to this problem documented here, including this little gem:
CREATE FUNCTION dbo.Split (@sep char(1), @s varchar(512))
RETURNS table
AS
RETURN (
WITH Pieces(pn, start, stop) AS (
SELECT 1, 1, CHARINDEX(@sep, @s)
UNION ALL
SELECT pn + 1, stop + 1, CHARINDEX(@sep, @s, stop + 1)
FROM Pieces
WHERE stop > 0
)
SELECT pn,
SUBSTRING(@s, start, CASE WHEN stop > 0 THEN stop-start ELSE 512 END) AS s
FROM Pieces
)
You can also achieve this effect using XML, as seen here, which removes the limitation of the answers provided which all seem to include recursion in some fashion. The particular use I've made here allows for up to a 32-character delimiter, but that could be increased however large it needs to be.
create FUNCTION [dbo].[Split] (@sep VARCHAR(32), @s VARCHAR(MAX))
RETURNS TABLE
AS
RETURN
(
SELECT r.value('.','VARCHAR(MAX)') as Item
FROM (SELECT CONVERT(XML, N'<root><r>' + REPLACE(REPLACE(REPLACE(@s,'& ','& '),'<','<'), @sep, '</r><r>') + '</r></root>') as valxml) x
CROSS APPLY x.valxml.nodes('//root/r') AS RECORDS(r)
)
Then you can invoke it using:
SELECT * FROM dbo.Split(' ', 'I hate bunnies')
Which returns:
-----------
|I |
|---------|
|hate |
|---------|
|bunnies |
-----------
CREATE FUNCTION [dbo].[Split] (@sep VARCHAR(32), @s VARCHAR(MAX))
RETURNS TABLE
AS
RETURN
(
SELECT r.value('.','VARCHAR(MAX)') as Item
FROM (SELECT CONVERT(XML, N'<root><r>' + REPLACE(@s, @sep, '</r><r>') + '</r></root>') as valxml) x
CROSS APPLY x.valxml.nodes('//root/r') AS RECORDS(r)
)
I use this function (SQL Server 2005 and above).
create function [dbo].[Split]
(
@string nvarchar(4000),
@delimiter nvarchar(10)
)
returns @table table
(
[Value] nvarchar(4000)
)
begin
declare @nextString nvarchar(4000)
declare @pos int, @nextPos int
set @nextString = ''
set @string = @string + @delimiter
set @pos = charindex(@delimiter, @string)
set @nextPos = 1
while (@pos <> 0)
begin
set @nextString = substring(@string, 1, @pos - 1)
insert into @table
(
[Value]
)
values
(
@nextString
)
set @string = substring(@string, @pos + len(@delimiter), len(@string))
set @nextPos = @pos
set @pos = charindex(@delimiter, @string)
end
return
end
For the particular case of splitting strings into words I've come across another solution for SQL Server 2008.
with testTable AS
(
SELECT 1 AS Id, N'how now brown cow' AS txt UNION ALL
SELECT 2, N'she sells sea shells upon the sea shore' UNION ALL
SELECT 3, N'red lorry yellow lorry' UNION ALL
SELECT 4, N'the quick brown fox jumped over the lazy dog'
)
SELECT display_term, COUNT(*) As Cnt
FROM testTable
CROSS APPLY sys.dm_fts_parser('"' + txt + '"', 1033, 0,0)
GROUP BY display_term
HAVING COUNT(*) > 1
ORDER BY Cnt DESC
Returns
display_term Cnt
------------------------------ -----------
the 3
brown 2
lorry 2
sea 2
Slight modification of the solution above so it works with variable-length delimiters.
create FUNCTION dbo.fn_Split2 (@sep nvarchar(10), @s nvarchar(4000))
RETURNS table
AS
RETURN (
WITH Pieces(pn, start, stop) AS (
SELECT 1, 1, CHARINDEX(@sep, @s)
UNION ALL
SELECT pn + 1, stop + (datalength(@sep)/2), CHARINDEX(@sep, @s, stop + (datalength(@sep)/2))
FROM Pieces
WHERE stop > 0
)
SELECT pn,
SUBSTRING(@s, start, CASE WHEN stop > 0 THEN stop-start ELSE 4000 END) AS s
FROM Pieces
)
NB: I've used datalength() since len() reports incorrectly if there are trailing spaces.
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