Get free disk space with df to just display free space in kb?

Question

I'm trying to output the amount of free disk space on the filesystem /example.

If I run the command df -k /example I can get good information about available disk space in kb but only by being human and actually looking at it.

I need to take this data and use it somewhere else in my shell script. I initially thought about using cut but then my script wont be portable to other disks as free disk space will vary and cut will not produce accurate results.

How can I get output of just the free disk-space of example in kb?

Answer 1

To get the output of df to display the data in kb you just need to use the -k flag:

df -k 

Also, if you specify a filesystem to df, you will get the values for that specific, instead of all of them:

df -k /example 

---

Regarding the body of your question: you want to extract the amount of free disk space on a given filesystem. This will require some processing.

Given a normal df -k output:

$ df -k /tmp Filesystem     1K-blocks    Used Available Use% Mounted on /dev/sda1        7223800 4270396   2586456  63% / 

You can get the Available (4th column) for example with awk or cut (previously piping to tr to squeeze-repeats (-s) for spaces):

$ df -k /tmp | tail -1 | awk '{print $4}' 2586456 $ df -k /tmp | tail -1 | tr -s ' ' | cut -d' ' -f4 2586456 

As always, if you want to store the result in a variable, use the var=$(command) syntax like this:

$ myUsed=$(df -k /tmp | tail -1 | awk '{print $4}') $ echo "$myUsed" 2586456 

Also, from the comment by Tim Bunce you can handle long filesystem names using --direct to get a - instead, so that it does not print a line that breaks the engine:

$ df -k --direct /tmp Filesystem     1K-blocks    Used Available Use% Mounted on -                7223800 4270396   2586456  63% / 

Answer 2

You can use stat(2) command to display free blocks and also to find out how large each block is, e.g.

stat -f --printf="%a %s\n" / 

will display number of free blocks (%a) on a given file system (/) followed by a block size (%s). To get size in kB, you can use bc(1) command as in the following example:

stat -f --printf="%a * %s / 1024\n" / | bc 

Finally, to put this into a variable is just a matter of using backtick substitution (or $() as in the first answer):

SOMEVAR=`stat -f --printf="%a * %s / 1024\n" / | bc`