XSLT: How to change an attribute value during <xsl:copy>?

Question

I have an XML document, and I want to change the values for one of the attributes.

First I copied everything from input to output using:

<xsl:template match="@*|node()">   <xsl:copy>     <xsl:apply-templates select="@*|node()"/>   </xsl:copy> </xsl:template> 

And now I want to change the value of the attribute "type" in any element named "property".

Answer 1

This problem has a classical solution: Using and overriding the identity template is one of the most fundamental and powerful XSLT design patterns:

<xsl:stylesheet version="1.0"   xmlns:xsl="http://www.w3.org/1999/XSL/Transform">     <xsl:output omit-xml-declaration="yes" indent="yes"/>      <xsl:param name="pNewType" select="'myNewType'"/>      <xsl:template match="node()|@*">         <xsl:copy>             <xsl:apply-templates select="node()|@*"/>         </xsl:copy>     </xsl:template>      <xsl:template match="property/@type">         <xsl:attribute name="type">             <xsl:value-of select="$pNewType"/>         </xsl:attribute>     </xsl:template> </xsl:stylesheet> 

When applied on this XML document:

<t>   <property>value1</property>   <property type="old">value2</property> </t> 

the wanted result is produced:

<t>   <property>value1</property>   <property type="myNewType">value2</property> </t>