XSLT with XML source that has a default namespace set to xmlns

Question

I have an XML document with a default namespace indicated at the root. Something like this:

<MyRoot xmlns="http://www.mysite.com">    <MyChild1>        <MyData>1234</MyData>     </MyChild1>  </MyRoot> 

The XSLT to parse the XML does not work as expected because of the default namespace, i.e. when I remove the namespace, everything works as expected.

Here is my XSLT:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"             xmlns:xs="http://www.w3.org/2001/XMLSchema">  <xsl:template match="/" >   <soap:Envelope xsl:version="1.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">    <soap:Body>      <NewRoot xmlns="http://wherever.com">        <NewChild>          <ChildID>ABCD</ChildID>          <ChildData>             <xsl:value-of select="/MyRoot/MyChild1/MyData"/>          </ChildData>        </NewChild>      </NewRoot>    </soap:Body>   </soap:Envelope>  </xsl:template> </xsl:stylesheet> 

What needs to be done with XSLT document so that translation works properly? What exactly needs to be done in XSLT document?

Answer 1

You need to declare the namespace in your XSLT, and use it in XPath expressions. E.g.:

<xsl:stylesheet ... xmlns:my="http://www.mysite.com">     <xsl:template match="/my:MyRoot"> ... </xsl:template>  </xsl:stylesheet> 

Note that you must provide some prefix if you want to refer to elements from that namespace in XPath. While you can just do xmlns="..." without the prefix, and it will work for literal result elements, it won't work for XPath - in XPath, an unprefixed name is always considered to be in namespace with blank URI, regardless of any xmlns="..." in scope.

Answer 2

If you use XSLT 2.0, specify xpath-default-namespace="http://www.example.com" in the stylesheet section.