Does XSLT have a Split() function?

Question

I have a string in a node and I'd like to split the string on '?' and return the last item in the array.

For example, in the block below:

<a>     <xsl:attribute name="href">         /newpage.aspx?<xsl:value-of select="someNode"/>     </xsl:attribute>     Link text </a> 

I'd like to split the someNode value.

Edit: Here's the VB.Net that I use to load the Xsl for my Asp.Net page:

Dim xslDocPath As String = HttpContext.Current.Server.MapPath("~/App_Data/someXslt.xsl") Dim myXsltSettings As New XsltSettings() Dim myXMLResolver As New XmlUrlResolver()  myXsltSettings.EnableScript = True myXsltSettings.EnableDocumentFunction = True  myXslDoc = New XslCompiledTransform(False) myXslDoc.Load(xslDocPath, myXsltSettings, myXMLResolver)  Dim myStringBuilder As New StringBuilder() Dim myXmlWriter As XmlWriter = Nothing  Dim myXmlWriterSettings As New XmlWriterSettings() myXmlWriterSettings.ConformanceLevel = ConformanceLevel.Auto myXmlWriterSettings.Indent = True myXmlWriterSettings.OmitXmlDeclaration = True  myXmlWriter = XmlWriter.Create(myStringBuilder, myXmlWriterSettings)  myXslDoc.Transform(xmlDoc, argumentList, myXmlWriter)  Return myStringBuilder.ToString() 

Update: here's an example of splitting XML on a particular node

Answer 1

Use a recursive method:

<xsl:template name="output-tokens">     <xsl:param name="list" />      <xsl:variable name="newlist" select="concat(normalize-space($list), ' ')" />      <xsl:variable name="first" select="substring-before($newlist, ' ')" />      <xsl:variable name="remaining" select="substring-after($newlist, ' ')" />      <id>         <xsl:value-of select="$first" />      </id>     <xsl:if test="$remaining">         <xsl:call-template name="output-tokens">             <xsl:with-param name="list" select="$remaining" />          </xsl:call-template>     </xsl:if> </xsl:template>