xpath select by attribute when attribute not present

Question

Short question: I would like to select all nodes that do not match an attribute (@type !='x') but also attribute doesn't exist (??). Currently, I'm getting nothing back, because the other nodes have no attribute at all.

Background: I have some XML. Note that one has type="feature" but all others have no 'type' attr.

<image type="feature"><description>X</description><url>media/designer_glass_tile_04.jpg</url><height></height><width/></image> <image><description>Designer Glass 05</description><url>media/designer_glass_tile_05.jpg</url><height></height><width/></image> <image><description>Designer Glass 06</description><url>media/designer_glass_tile_06.jpg</url><height></height><width/></image> <image><description>Designer Glass 07</description><url>media/designer_glass_tile_07.jpg</url><height></height><width/></image> <image><description>Designer Glass 08</description><url>media/designer_glass_tile_08.jpg</url><height></height><width/></image> 

And a XSL style:

        <div id="gallery">             <div id="feature" >                 <xsl:apply-templates select="image[@type='feature']"/>             </div>             <div id="thumbs">                 <xsl:apply-templates select="image[@type!='feature']"/>             </div>         </div> 

Answer 1

The following code will select all nodes where type attribute doesn't exist:

select="image[not(@type)]" 

Add this logic in your code.

Answer 2

Try using not() instead of != in the predicate...

   <div id="gallery">         <div id="feature" >             <xsl:apply-templates select="image[@type='feature']"/>         </div>         <div id="thumbs">             <xsl:apply-templates select="image[not(@type='feature')]"/>         </div>     </div>