trailing return type using decltype with a variadic template function

Question

I want to write a simple adder (for giggles) that adds up every argument and returns a sum with appropriate type. Currently, I've got this:

#include <iostream> using namespace std;  template <class T> T sum(const T& in) {    return in; }  template <class T, class... P> auto sum(const T& t, const P&... p) -> decltype(t + sum(p...)) {    return t + sum(p...); }  int main() {    cout << sum(5, 10.0, 22.2) << endl; } 

On GCC 4.5.1 this seems to work just fine for 2 arguments e.g. sum(2, 5.5) returns with 7.5. However, with more arguments than this, I get errors that sum() is simply not defined yet. If I declare sum() like this however:

template <class T, class P...> T sum(const T& t, const P&... p); 

Then it works for any number of arguments, but sum(2, 5.5) would return integer 7, which is not what I would expect. With more than two arguments I assume that decltype() would have to do some sort of recursion to be able to deduce the type of t + sum(p...). Is this legal C++0x? or does decltype() only work with non-variadic declarations? If that is the case, how would you write such a function?

Answer 1

I think the problem is that the variadic function template is only considered declared after you specified its return type so that sum in decltype can never refer to the variadic function template itself. But I'm not sure whether this is a GCC bug or C++0x simply doesn't allow this. My guess is that C++0x doesn't allow a "recursive" call in the ->decltype(expr) part.

As a workaround we can avoid this "recursive" call in ->decltype(expr) with a custom traits class:

#include <iostream> #include <type_traits> using namespace std;  template<class T> typename std::add_rvalue_reference<T>::type val();  template<class T> struct id{typedef T type;};  template<class T, class... P> struct sum_type; template<class T> struct sum_type<T> : id<T> {}; template<class T, class U, class... P> struct sum_type<T,U,P...> : sum_type< decltype( val<const T&>() + val<const U&>() ), P... > {}; 

This way, we can replace decltype in your program with typename sum_type<T,P...>::type and it will compile.

Edit: Since this actually returns decltype((a+b)+c) instead of decltype(a+(b+c)) which would be closer to how you use addition, you could replace the last specialization with this:

template<class T, class U, class... P> struct sum_type<T,U,P...> : id<decltype(       val<T>()     + val<typename sum_type<U,P...>::type>() )>{};