Consider the following snippet to test the upcoming C++17 feature decomposition declarations (formerly known as structured bindings)
#include <cassert>
#include <utility>
constexpr auto divmod(int n, int d)
{
return std::make_pair(n / d, n % d); // in g++7, also just std::pair{n/d, n%d}
}
int main()
{
constexpr auto [q, r] = divmod(10, 3);
static_assert(q == 3 && r ==1);
}
This fails on both g++7-SVN and clang-4.0-SVN with the message:
decomposition declaration cannot be declared 'constexpr'
Dropping the constexpr
definition and changing to a regular assert()
works on both compilers.
None of the WG21 papers on this feature mention the constexpr
keyword, neither in the positive nor the negative.
Question: why aren't decomposition declarations be allowed to be constexpr
? (apart from "because the Standard says so").
Question: why aren't decomposition declarations be allowed to be constexpr? (apart from "because the Standard says so").
There is no other reason. The standard says in [dcl.dcl] p8:
The decl-specifier-seq shall contain only the type-specifier
auto
(7.1.7.4) and cv-qualifiers.
That means it can't be declared with constexpr
.
This was the subject of a National Body comment on the C++17 CD, see US-95 in P0488R0:
Comment: There is no obvious reason why decomposition declarations cannot be declared as static, thread_local, or constexpr.
Proposed change: Allow constexpr, static, and thread_local to the permitted set of decl-specifiers.
Comments GB 16 and GB 17 are also related.
These comment were rejected for C++17 after review by the Evolution Working Group at the Nov 2016 meeting. It was unclear what some storage classes would mean on a structured binding declaration, and exactly how to change the specification to allow constexpr
(simply allowing it in the grammar wouldn't say what it means). A paper exploring the design space was requested. It should be possible to change this in future without breaking any code, but there wasn't time to do it for C++17.
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