shell script: bad interpreter: No such file or directory when using pwd

Question

I want to go through the files in a directory with a for loop but this comes up.

echo: bad interpreter: No such file or directory

code:

#!/bin/bash
count=0
dir=`pwd`
echo "$dir"
FILES=`ls $dir`
for file in $FILES
do
 if [ -f $file ]
 then
  count=$(($count + 1))
 fi
done
echo $count

Answer 1

I had the same problem. Removing #!/bin/bash did the trick for me. It seems that is not necessary to add where bash is located, since it is on the system path.

I found another solution here. Change

#!/bin/bash

for

#!/usr/bin/bash

Answer 2

Better do :

#!/bin/bash
count=0
dir="$PWD"
echo "$dir"

for file in "$dir"/*
do
 if [[ -f $file ]]
 then
  ((count++))
 fi
done
echo $count

or a simplest/shortest solution :

#!/bin/bash

echo "$PWD"

for file; do
 [[ -f $file ]] && ((count++))
done

echo $count