I want to download a bunch of files named with ISO-8601 dates. Is there a simple way to do this using bash+GNU coreutils? (Or some trick to make wget/curl to generate the list automatically, but I find that unlikely)
Similar to this question, but not restricted to weekdays: How to generate a range of nonweekend dates using tools available in bash?. I guess that there is a simpler way to do it without that restriction.
Also related to How to generate date range for random data on bash, but not restricted to a single year.
If you have GNU date
, you could do use either a for
loop in any POSIX-compliant shell:
# with "for" for i in {1..5}; do # ISO 8601 (e.g. 2020-02-20) using -I date -I -d "2014-06-28 +$i days" # custom format using + date +%Y/%m/%d -d "2014-06-28 +$i days" done
or an until
loop, this time using Bash's extended test [[
:
# with "until" d="2014-06-29" until [[ $d > 2014-07-03 ]]; do echo "$d" d=$(date -I -d "$d + 1 day") done
Note that non-ancient versions of sh
will also do lexicographical comparison if you change the condition to [ "$d" \> 2014-07-03 ]
.
Output from either of those loops:
2014-06-29 2014-06-30 2014-07-01 2014-07-02 2014-07-03
For a more portable way to do the same thing, you could use a Perl script:
use strict; use warnings; use Time::Piece; use Time::Seconds; use File::Fetch; my ($t, $end) = map { Time::Piece->strptime($_, "%Y-%m-%d") } @ARGV; while ($t <= $end) { my $url = "http://www.example.com/" . $t->strftime("%F") . ".log"; my $ff = File::Fetch->new( uri => $url ); my $where = $ff->fetch( to => '.' ); # download to current directory $t += ONE_DAY; }
Time::Piece, Time::Seconds and File::Fetch are all core modules. Use it like perl wget.pl 2014-06-29 2014-07-03
.
Using GNU date and bash:
start=2014-12-29 end=2015-01-03 while ! [[ $start > $end ]]; do echo $start start=$(date -d "$start + 1 day" +%F) done
2014-12-29 2014-12-30 2014-12-31 2015-01-01 2015-01-02 2015-01-03
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