So, I was wondering if there was a bash command that lets me fork a process which sleeps for several seconds, then executes a command.
Here's an example:
sleep 30 'echo executing...' &
^This doesn't actually work (because the sleep command only takes the time argument), but is there something that could do something like this? So, basically, a sleep command that takes a time argument and something to execute when the interval is completed? I want to be able to fork it into a different process then continue processing the shell script.
Also, I know I could write a simple script that does this, but due to some restraints to the situation (I'm actually passing this through a ssh call), I'd rather not do that.
How to Use the Bash Sleep Command. Sleep is a very versatile command with a very simple syntax. It is as easy as typing sleep N . This will pause your script for N seconds, with N being either a positive integer or a floating point number.
/bin/sleep is Linux or Unix command to delay for a specified amount of time. You can suspend the calling shell script for a specified time. For example, pause for 10 seconds or stop execution for 2 mintues. In other words, the sleep command pauses the execution on the next shell command for a given time.
Use the sleep command. Example: sleep . 5 # Waits 0.5 second.
You can do
(sleep 30 && command ...)&
Using &&
is safer than ;
because it ensures that command ...
will run only if the sleep timer expires.
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