How to get the number of files in a folder as a variable?

Question

Using bash, how can one get the number of files in a folder, excluding directories from a shell script without the interpreter complaining?

With the help of a friend, I've tried

$files=$(find ../ -maxdepth 1 -type f | sort -n) $num=$("ls -l" | "grep ^-" | "wc -l") 

which returns from the command line:

../1-prefix_blended_fused.jpg: No such file or directory ls -l :  command not found grep ^-: command not found wc -l:   command not found 

respectively. These commands work on the command line, but NOT with a bash script.

Given a file filled with image files formatted like 1-pano.jpg, I want to grab all the images in the directory to get the largest numbered file to tack onto the next image being processed.

Why the discrepancy?

Answer 1

The quotes are causing the error messages.

To get a count of files in the directory:

shopt -s nullglob numfiles=(*) numfiles=${#numfiles[@]} 

which creates an array and then replaces it with the count of its elements. This will include files and directories, but not dotfiles or . or .. or other dotted directories.

Use nullglob so an empty directory gives a count of 0 instead of 1.

You can instead use find -type f or you can count the directories and subtract:

# continuing from above numdirs=(*/) numdirs=${#numdirs[@]} (( numfiles -= numdirs )) 

Also see "How can I find the latest (newest, earliest, oldest) file in a directory?"

You can have as many spaces as you want inside an execution block. They often aid in readability. The only downside is that they make the file a little larger and may slow initial parsing (only) slightly. There are a few places that must have spaces (e.g. around [, [[, ], ]] and = in comparisons) and a few that must not (e.g. around = in an assignment.