How do I find the size of a 2D array in C++? Is there any predefined function like sizeof
to determine the size of the array?
Also, can anyone tell me how to detect an error in the getvalue
method for arrays while trying to get a value which is not set?
We use arrayname. length to determine the number of rows in a 2D array because the length of a 2D array is equal to the number of rows it has. The number of columns may vary row to row, which is why the number of rows is used as the length of the 2D array.
We can find the size of an array using the sizeof() operator as shown: // Finds size of arr[] and stores in 'size' int size = sizeof(arr)/sizeof(arr[0]);
If the array is declared using automatic storage duration, then the size limit is remarkably small, at around 1Mb. If you're using dynamic storage duration (using new and new[] ), then then limit is much higher.
C++, Using 2D array (max size 100*26) - LeetCode Discuss.
Suppose you were only allowed to use array then you could find the size of 2-d array by the following way.
int ary[][5] = { {1, 2, 3, 4, 5}, {6, 7, 8, 9, 0} }; int rows = sizeof ary / sizeof ary[0]; // 2 rows int cols = sizeof ary[0] / sizeof(int); // 5 cols
#include <bits/stdc++.h> using namespace std; int main(int argc, char const *argv[]) { int arr[6][5] = { {1,2,3,4,5}, {1,2,3,4,5}, {1,2,3,4,5}, {1,2,3,4,5}, {1,2,3,4,5}, {1,2,3,4,5} }; int rows = sizeof(arr)/sizeof(arr[0]); int cols = sizeof(arr[0])/sizeof(arr[0][0]); cout<<rows<<" "<<cols<<endl; return 0; }
Output: 6 5
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