Get size of terminal window (rows/columns)

Question

Is there any reliable way of getting the number of columns/rows of the current output terminal window?

I want to retrieve these numbers in a C/C++ program.

I'm looking for a GNU/Linux solution primarily, but also need a Windows solution.

Answer 1

On Windows, use the following code to print the size of the console window (borrowed from here):

#include <windows.h>

int main(int argc, char *argv[]) 
{
    CONSOLE_SCREEN_BUFFER_INFO csbi;
    int columns, rows;

    GetConsoleScreenBufferInfo(GetStdHandle(STD_OUTPUT_HANDLE), &csbi);
    columns = csbi.srWindow.Right - csbi.srWindow.Left + 1;
    rows = csbi.srWindow.Bottom - csbi.srWindow.Top + 1;

    printf("columns: %d\n", columns);
    printf("rows: %d\n", rows);
    return 0;
}

---

On Linux, use the following instead (borrowed from here):

#include <sys/ioctl.h>
#include <stdio.h>
#include <unistd.h>

int main (int argc, char **argv)
{
    struct winsize w;
    ioctl(STDOUT_FILENO, TIOCGWINSZ, &w);

    printf ("lines %d\n", w.ws_row);
    printf ("columns %d\n", w.ws_col);
    return 0;  // make sure your main returns int
}

Answer 2

For Unix(-based), use ioctl(2) and TIOCGWINSZ:

#include <sys/ioctl.h> //ioctl() and TIOCGWINSZ
#include <unistd.h> // for STDOUT_FILENO
// ...

struct winsize size;
ioctl(STDOUT_FILENO, TIOCGWINSZ, &size);

/* size.ws_row is the number of rows, size.ws_col is the number of columns. */

// ...

Also, while I haven't touched Windows in the last five years, GetConsoleScreenBufferInfo() should help you get the console window size.

Answer 3

To expand @herohuyongtao answer for Windows. The .srWindow property gives the answer to the size of the console window, i.e. visible rows and cols. This doesn't say what is the actual available screen buffer width and height, which could be larger if window contains scroll bars. If this is the case, use .dwSize:

CONSOLE_SCREEN_BUFFER_INFO sbInfo;
GetConsoleScreenBufferInfo(GetStdHandle(STD_OUTPUT_HANDLE), &sbInfo);
int availableColumns = sbInfo.dwSize.X;
int availableRows = sbInfo.dwSize.Y;

Answer 4

Here is a solution that works in both Windows and Linux:

#if defined(_WIN32)
#define WIN32_LEAN_AND_MEAN
#define VC_EXTRALEAN
#include <Windows.h>
#elif defined(__linux__)
#include <sys/ioctl.h>
#endif // Windows/Linux

void get_terminal_size(int& width, int& height) {
#if defined(_WIN32)
    CONSOLE_SCREEN_BUFFER_INFO csbi;
    GetConsoleScreenBufferInfo(GetStdHandle(STD_OUTPUT_HANDLE), &csbi);
    width = (int)(csbi.srWindow.Right-csbi.srWindow.Left+1);
    height = (int)(csbi.srWindow.Bottom-csbi.srWindow.Top+1);
#elif defined(__linux__)
    struct winsize w;
    ioctl(fileno(stdout), TIOCGWINSZ, &w);
    width = (int)(w.ws_col);
    height = (int)(w.ws_row);
#endif // Windows/Linux
}

#include <iostream>
using namespace std;
int main() {
    int width=0, height=0;
    get_terminal_size(width, height);
    cout << "width=" << width << ", height=" << height << endl;
    cin.get();
    return 0;
}