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How to do the equivalent of pass by reference for primitives in Java

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How do you pass a reference to a primitive type in Java?

When passing Java objects, you're passing an object reference, which makes it possible to modify the object's member variables. If you want to pass a primitive data type by reference, you need to wrap it in an object. The easiest of all is to pass it as an array (or even a Vector).

Is Java pass by value for primitives?

In Java, Objects are passed by reference, and primitives are passed by value.

Are primitive types passed by reference?

Objects are passed by reference and primitive types are passed by value. A correct statement would be: Object references are passed by value, as are primitive types. Thus, Java passes by value, not by reference, in all cases.


You have several choices. The one that makes the most sense really depends on what you're trying to do.

Choice 1: make toyNumber a public member variable in a class

class MyToy {
  public int toyNumber;
}

then pass a reference to a MyToy to your method.

void play(MyToy toy){  
    System.out.println("Toy number in play " + toy.toyNumber);   
    toy.toyNumber++;  
    System.out.println("Toy number in play after increement " + toy.toyNumber);   
}

Choice 2: return the value instead of pass by reference

int play(int toyNumber){  
    System.out.println("Toy number in play " + toyNumber);   
    toyNumber++;  
    System.out.println("Toy number in play after increement " + toyNumber);   
    return toyNumber
}

This choice would require a small change to the callsite in main so that it reads, toyNumber = temp.play(toyNumber);.

Choice 3: make it a class or static variable

If the two functions are methods on the same class or class instance, you could convert toyNumber into a class member variable.

Choice 4: Create a single element array of type int and pass that

This is considered a hack, but is sometimes employed to return values from inline class invocations.

void play(int [] toyNumber){  
    System.out.println("Toy number in play " + toyNumber[0]);   
    toyNumber[0]++;  
    System.out.println("Toy number in play after increement " + toyNumber[0]);   
}

Java is not call by reference it is call by value only

But all variables of object type are actually pointers.

So if you use a Mutable Object you will see the behavior you want

public class XYZ {

    public static void main(String[] arg) {
        StringBuilder toyNumber = new StringBuilder("5");
        play(toyNumber);
        System.out.println("Toy number in main " + toyNumber);
    }

    private static void play(StringBuilder toyNumber) {
        System.out.println("Toy number in play " + toyNumber);
        toyNumber.append(" + 1");
        System.out.println("Toy number in play after increement " + toyNumber);
    }
}

Output of this code:

run:
Toy number in play 5
Toy number in play after increement 5 + 1
Toy number in main 5 + 1
BUILD SUCCESSFUL (total time: 0 seconds)

You can see this behavior in Standard libraries too. For example Collections.sort(); Collections.shuffle(); These methods does not return a new list but modifies it's argument object.

    List<Integer> mutableList = new ArrayList<Integer>();

    mutableList.add(1);
    mutableList.add(2);
    mutableList.add(3);
    mutableList.add(4);
    mutableList.add(5);

    System.out.println(mutableList);

    Collections.shuffle(mutableList);

    System.out.println(mutableList);

    Collections.sort(mutableList);

    System.out.println(mutableList);

Output of this code:

run:
[1, 2, 3, 4, 5]
[3, 4, 1, 5, 2]
[1, 2, 3, 4, 5]
BUILD SUCCESSFUL (total time: 0 seconds)

Make a

class PassMeByRef { public int theValue; }

then pass a reference to an instance of it. Note that a method that mutates state through its arguments is best avoided, especially in parallel code.


You cannot pass primitives by reference in Java. All variables of object type are actually pointers, of course, but we call them "references", and they are also always passed by value.

In a situation where you really need to pass a primitive by reference, what people will do sometimes is declare the parameter as an array of primitive type, and then pass a single-element array as the argument. So you pass a reference int[1], and in the method, you can change the contents of the array.


For a quick solution, you can use AtomicInteger or any of the atomic variables which will let you change the value inside the method using the inbuilt methods. Here is sample code:

import java.util.concurrent.atomic.AtomicInteger;


public class PrimitivePassByReferenceSample {

    /**
     * @param args
     */
    public static void main(String[] args) {

        AtomicInteger myNumber = new AtomicInteger(0);
        System.out.println("MyNumber before method Call:" + myNumber.get());
        PrimitivePassByReferenceSample temp = new PrimitivePassByReferenceSample() ;
        temp.changeMyNumber(myNumber);
        System.out.println("MyNumber After method Call:" + myNumber.get());


    }

     void changeMyNumber(AtomicInteger myNumber) {
        myNumber.getAndSet(100);

    }

}

Output:

MyNumber before method Call:0

MyNumber After method Call:100

public static void main(String[] args) {
    int[] toyNumber = new int[] {5};
    NewClass temp = new NewClass();
    temp.play(toyNumber);
    System.out.println("Toy number in main " + toyNumber[0]);
}

void play(int[] toyNumber){
    System.out.println("Toy number in play " + toyNumber[0]);
    toyNumber[0]++;
    System.out.println("Toy number in play after increement " + toyNumber[0]);
}