How to add src files in the middle of a pipe

Question

I want to process some files with 'coffee', add some js files, concat and minify.

This does not work, coffee fails on the regular js files:

gulp.task 'build-js', ->   gulp.src([       "bower_components/mbdev-core/dist/js/db.js"       "bower_components/mbdev-core/dist/js/utils.js"       "src/js/config/app.coffee"       "src/js/config/app-db.coffee"                     "src/js/accounts/accounts.coffee"       "src/js/budget_items/budget_items.coffee"       "src/js/line_items/line_items.coffee"       "src/js/misc/misc.coffee"       "src/js/reports/report_generators.coffee"       "src/js/reports/reports.coffee"    ])   .pipe(coffee()).on('error', gutil.log)   .pipe(concat('app.js'))   .pipe(gulp.dest('public/js')) 

Is there a way to add files after the coffee part?

Answer 1

You don't need to add files to the original src, but rather to use coffee only "if"...

So, use gulp-if

gulp.task('task', function() {   gulp.src('./stuff/*')     .pipe(gulpif(/[.]coffee$/, coffee()))     .pipe(gulp.dest('./dist/')); }); 

See here more about gulp-if.