How do I convert a string to a list of chars?

Question

Since a string supports iteration but not indexing, I would like to convert a string into a list of chars. I have "abc" and I want ['a', 'b', 'c'].

It can be any type as long as I can index into it. A Vec<char> or a [char; 3] would be fine, other ideas would also be interesting!

Faster would be better since I am dealing with very long strings. A version that is more efficient when assuming that the string is ASCII would also be cool.

Answer 1

Use the chars method on String or str:

fn main() {     let s = "Hello world!";     let char_vec: Vec<char> = s.chars().collect();     for c in char_vec {         println!("{}", c);     } } 

Here you have a live example

Answer 2

I've already come to this solution:

let chars: Vec<char> = input.chars().collect(); 

In a comment somebody suggested using .split("") but it seems to be implemented in a way that is annoying for this case:

println!("{:?}", "abc".split("").collect::<Vec<&str>>()); 

gives ["", "a", "b", "c", ""]