How can I zip more than two iterators?

Question

Is there a more direct and readable way to accomplish the following:

fn main() {     let a = [1, 2, 3];     let b = [4, 5, 6];     let c = [7, 8, 9];     let iter = a.iter()         .zip(b.iter())         .zip(c.iter())         .map(|((x, y), z)| (x, y, z)); } 

That is, how can I build an iterator from n iterables which yields n-tuples?

Answer 1

You can use the izip!() macro from the crate itertools, which implements this for arbitrary many iterators:

use itertools::izip;  fn main() {      let a = [1, 2, 3];     let b = [4, 5, 6];     let c = [7, 8, 9];      // izip!() accepts iterators and/or values with IntoIterator.     for (x, y, z) in izip!(&a, &b, &c) {      } } 

You would have to add a dependency on itertools in Cargo.toml, use whatever version is the latest. Example:

[dependencies] itertools = "0.8"