I am new to jq and facing an issue while parsing my json
I have a json stored in a variable like this
temp='{ "1": { "my_name": "one" }, "2": { "my_name": "two" } }'
Now I need to get the value of my_name for both other entries
I have tried something like this
echo $temp | jq '.1' //out put 0.1
I was assuming to get { "my_name": "one" }
And similarly to get my_name value I did
echo $temp | jq '.1.my_name' // Its output is giving me error
Can any one please help to identify what is wrong with my syntax and how can I correct it.
Put the key first in double quotes and then escape the first dot by wrapping it using single quotes.
The JQ command is used to transform JSON data into a more readable format and print it to the standard output on Linux. The JQ command is built around filters which are used to find and print only the required data from a JSON file.
Just the number gets interpreted as a float. You need to use it in a context where it is unambiguously a key string.
echo "$temp" | jq '.["1"]["my_name"]'
and
echo "$temp" | jq '.["1"]'
to get the containing dict.
With a sufficiently new jq
(I think >= 1.4) you can also say
echo "$temp" | jq '."1".my_name'
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