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Use re.search() to extract a substring matching a regular expression pattern. Specify the regular expression pattern as the first parameter and the target string as the second parameter. \d matches a digit character, and + matches one or more repetitions of the preceding pattern.
To run a “whole words only” search using a regular expression, simply place the word between two word boundaries, as we did with ‹ \bcat\b ›. The first ‹ \b › requires the ‹ c › to occur at the very start of the string, or after a nonword character.
The metacharacter \b is an anchor like the caret and the dollar sign. It matches at a position that is called a “word boundary”. This match is zero-length. There are three different positions that qualify as word boundaries: Before the first character in the string, if the first character is a word character.
Use ( ) in regexp and group(1) in python to retrieve the captured string (re.search will return None if it doesn't find the result, so don't use group() directly):
title_search = re.search('<title>(.*)</title>', html, re.IGNORECASE)
if title_search:
title = title_search.group(1)
Note that starting Python 3.8, and the introduction of assignment expressions (PEP 572) (:= operator), it's possible to improve a bit on Krzysztof Krasoń's solution by capturing the match result directly within the if condition as a variable and re-use it in the condition's body:
# pattern = '<title>(.*)</title>'
# text = '<title>hello</title>'
if match := re.search(pattern, text, re.IGNORECASE):
title = match.group(1)
# hello
Try using capturing groups:
title = re.search('<title>(.*)</title>', html, re.IGNORECASE).group(1)
May I recommend you to Beautiful Soup. Soup is a very good lib to parse all of your html document.
soup = BeatifulSoup(html_doc)
titleName = soup.title.name
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