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The getProtocol() function is a part of URL class. The function getProtocol() returns the Protocol of a specified URL.
The getHost() method of URL class returns the hostname of the URL. This method will return the IPv6 address enclosed in square brackets ('['and']').
If you only want to return the hostname value (excluding the port number), use the window. location. hostname method instead. This will return a string value containing the hostname and, if the port value is non-empty, a : symbol along with the port number of the URL.
Answer: Use the window. location. href Property location. href property to get the entire URL of the current page which includes host name, query string, fragment identifier, etc. The following example will display the current url of the page on click of the button.
You should be able to do it with urlparse (docs: python2, python3):
from urllib.parse import urlparse
# from urlparse import urlparse # Python 2
parsed_uri = urlparse('http://stackoverflow.com/questions/1234567/blah-blah-blah-blah' )
result = '{uri.scheme}://{uri.netloc}/'.format(uri=parsed_uri)
print(result)
# gives
'http://stackoverflow.com/'
https://github.com/john-kurkowski/tldextract
This is a more verbose version of urlparse. It detects domains and subdomains for you.
From their documentation:
>>> import tldextract
>>> tldextract.extract('http://forums.news.cnn.com/')
ExtractResult(subdomain='forums.news', domain='cnn', suffix='com')
>>> tldextract.extract('http://forums.bbc.co.uk/') # United Kingdom
ExtractResult(subdomain='forums', domain='bbc', suffix='co.uk')
>>> tldextract.extract('http://www.worldbank.org.kg/') # Kyrgyzstan
ExtractResult(subdomain='www', domain='worldbank', suffix='org.kg')
ExtractResult is a namedtuple, so it's simple to access the parts you want.
>>> ext = tldextract.extract('http://forums.bbc.co.uk')
>>> ext.domain
'bbc'
>>> '.'.join(ext[:2]) # rejoin subdomain and domain
'forums.bbc'
from urllib.parse import urlsplit
url = "http://stackoverflow.com/questions/9626535/get-domain-name-from-url"
base_url = "{0.scheme}://{0.netloc}/".format(urlsplit(url))
print(base_url)
# http://stackoverflow.com/
>>> import urlparse
>>> url = 'http://stackoverflow.com/questions/1234567/blah-blah-blah-blah'
>>> urlparse.urljoin(url, '/')
'http://stackoverflow.com/'
Pure string operations :):
>>> url = "http://stackoverflow.com/questions/9626535/get-domain-name-from-url"
>>> url.split("//")[-1].split("/")[0].split('?')[0]
'stackoverflow.com'
>>> url = "stackoverflow.com/questions/9626535/get-domain-name-from-url"
>>> url.split("//")[-1].split("/")[0].split('?')[0]
'stackoverflow.com'
>>> url = "http://foo.bar?haha/whatever"
>>> url.split("//")[-1].split("/")[0].split('?')[0]
'foo.bar'
That's all, folks.
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