Enhanced REP MOVSB for memcpy

Question

I would like to use enhanced REP MOVSB (ERMSB) to get a high bandwidth for a custom memcpy.

ERMSB was introduced with the Ivy Bridge microarchitecture. See the section "Enhanced REP MOVSB and STOSB operation (ERMSB)" in the Intel optimization manual if you don't know what ERMSB is.

The only way I know to do this directly is with inline assembly. I got the following function from https://groups.google.com/forum/#!topic/gnu.gcc.help/-Bmlm_EG_fE

static inline void *__movsb(void *d, const void *s, size_t n) {   asm volatile ("rep movsb"                 : "=D" (d),                   "=S" (s),                   "=c" (n)                 : "0" (d),                   "1" (s),                   "2" (n)                 : "memory");   return d; } 

When I use this however, the bandwidth is much less than with memcpy. __movsb gets 15 GB/s and memcpy get 26 GB/s with my i7-6700HQ (Skylake) system, Ubuntu 16.10, DDR4@2400 MHz dual channel 32 GB, GCC 6.2.

Why is the bandwidth so much lower with REP MOVSB? What can I do to improve it?

Here is the code I used to test this.

//gcc -O3 -march=native -fopenmp foo.c #include <stdlib.h> #include <string.h> #include <stdio.h> #include <stddef.h> #include <omp.h> #include <x86intrin.h>  static inline void *__movsb(void *d, const void *s, size_t n) {   asm volatile ("rep movsb"                 : "=D" (d),                   "=S" (s),                   "=c" (n)                 : "0" (d),                   "1" (s),                   "2" (n)                 : "memory");   return d; }  int main(void) {   int n = 1<<30;    //char *a = malloc(n), *b = malloc(n);    char *a = _mm_malloc(n,4096), *b = _mm_malloc(n,4096);   memset(a,2,n), memset(b,1,n);    __movsb(b,a,n);   printf("%d\n", memcmp(b,a,n));    double dtime;    dtime = -omp_get_wtime();   for(int i=0; i<10; i++) __movsb(b,a,n);   dtime += omp_get_wtime();   printf("dtime %f, %.2f GB/s\n", dtime, 2.0*10*1E-9*n/dtime);    dtime = -omp_get_wtime();   for(int i=0; i<10; i++) memcpy(b,a,n);   dtime += omp_get_wtime();   printf("dtime %f, %.2f GB/s\n", dtime, 2.0*10*1E-9*n/dtime);   } 

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The reason I am interested in rep movsb is based off these comments

Note that on Ivybridge and Haswell, with buffers to large to fit in MLC you can beat movntdqa using rep movsb; movntdqa incurs a RFO into LLC, rep movsb does not... rep movsb is significantly faster than movntdqa when streaming to memory on Ivybridge and Haswell (but be aware that pre-Ivybridge it is slow!)

What's missing/sub-optimal in this memcpy implementation?

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Here are my results on the same system from tinymembnech.

 C copy backwards                                     :   7910.6 MB/s (1.4%)  C copy backwards (32 byte blocks)                    :   7696.6 MB/s (0.9%)  C copy backwards (64 byte blocks)                    :   7679.5 MB/s (0.7%)  C copy                                               :   8811.0 MB/s (1.2%)  C copy prefetched (32 bytes step)                    :   9328.4 MB/s (0.5%)  C copy prefetched (64 bytes step)                    :   9355.1 MB/s (0.6%)  C 2-pass copy                                        :   6474.3 MB/s (1.3%)  C 2-pass copy prefetched (32 bytes step)             :   7072.9 MB/s (1.2%)  C 2-pass copy prefetched (64 bytes step)             :   7065.2 MB/s (0.8%)  C fill                                               :  14426.0 MB/s (1.5%)  C fill (shuffle within 16 byte blocks)               :  14198.0 MB/s (1.1%)  C fill (shuffle within 32 byte blocks)               :  14422.0 MB/s (1.7%)  C fill (shuffle within 64 byte blocks)               :  14178.3 MB/s (1.0%)  ---  standard memcpy                                      :  12784.4 MB/s (1.9%)  standard memset                                      :  30630.3 MB/s (1.1%)  ---  MOVSB copy                                           :   8712.0 MB/s (2.0%)  MOVSD copy                                           :   8712.7 MB/s (1.9%)  SSE2 copy                                            :   8952.2 MB/s (0.7%)  SSE2 nontemporal copy                                :  12538.2 MB/s (0.8%)  SSE2 copy prefetched (32 bytes step)                 :   9553.6 MB/s (0.8%)  SSE2 copy prefetched (64 bytes step)                 :   9458.5 MB/s (0.5%)  SSE2 nontemporal copy prefetched (32 bytes step)     :  13103.2 MB/s (0.7%)  SSE2 nontemporal copy prefetched (64 bytes step)     :  13179.1 MB/s (0.9%)  SSE2 2-pass copy                                     :   7250.6 MB/s (0.7%)  SSE2 2-pass copy prefetched (32 bytes step)          :   7437.8 MB/s (0.6%)  SSE2 2-pass copy prefetched (64 bytes step)          :   7498.2 MB/s (0.9%)  SSE2 2-pass nontemporal copy                         :   3776.6 MB/s (1.4%)  SSE2 fill                                            :  14701.3 MB/s (1.6%)  SSE2 nontemporal fill                                :  34188.3 MB/s (0.8%) 

Note that on my system SSE2 copy prefetched is also faster than MOVSB copy.

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In my original tests I did not disable turbo. I disabled turbo and tested again and it does not appear to make much of a difference. However, changing the power management does make a big difference.

When I do

sudo cpufreq-set -r -g performance 

I sometimes see over 20 GB/s with rep movsb.

with

sudo cpufreq-set -r -g powersave 

the best I see is about 17 GB/s. But memcpy does not seem to be sensitive to the power management.

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I checked the frequency (using turbostat) with and without SpeedStep enabled, with performance and with powersave for idle, a 1 core load and a 4 core load. I ran Intel's MKL dense matrix multiplication to create a load and set the number of threads using OMP_SET_NUM_THREADS. Here is a table of the results (numbers in GHz).

              SpeedStep     idle      1 core    4 core powersave     OFF           0.8       2.6       2.6 performance   OFF           2.6       2.6       2.6 powersave     ON            0.8       3.5       3.1 performance   ON            3.5       3.5       3.1 

This shows that with powersave even with SpeedStep disabled the CPU still clocks down to the idle frequency of 0.8 GHz. It's only with performance without SpeedStep that the CPU runs at a constant frequency.

I used e.g sudo cpufreq-set -r performance (because cpufreq-set was giving strange results) to change the power settings. This turns turbo back on so I had to disable turbo after.

Answer 1

This is a topic pretty near to my heart and recent investigations, so I'll look at it from a few angles: history, some technical notes (mostly academic), test results on my box, and finally an attempt to answer your actual question of when and where rep movsb might make sense.

Partly, this is a call to share results - if you can run Tinymembench and share the results along with details of your CPU and RAM configuration it would be great. Especially if you have a 4-channel setup, an Ivy Bridge box, a server box, etc.

History and Official Advice

The performance history of the fast string copy instructions has been a bit of a stair-step affair - i.e., periods of stagnant performance alternating with big upgrades that brought them into line or even faster than competing approaches. For example, there was a jump in performance in Nehalem (mostly targeting startup overheads) and again in Ivy Bridge (most targeting total throughput for large copies). You can find decade-old insight on the difficulties of implementing the rep movs instructions from an Intel engineer in this thread.

For example, in guides preceding the introduction of Ivy Bridge, the typical advice is to avoid them or use them very carefully¹.

The current (well, June 2016) guide has a variety of confusing and somewhat inconsistent advice, such as²:

The specific variant of the implementation is chosen at execution time based on data layout, alignment and the counter (ECX) value. For example, MOVSB/STOSB with the REP prefix should be used with counter value less than or equal to three for best performance.

So for copies of 3 or less bytes? You don't need a rep prefix for that in the first place, since with a claimed startup latency of ~9 cycles you are almost certainly better off with a simple DWORD or QWORD mov with a bit of bit-twiddling to mask off the unused bytes (or perhaps with 2 explicit byte, word movs if you know the size is exactly three).

They go on to say:

String MOVE/STORE instructions have multiple data granularities. For efficient data movement, larger data granularities are preferable. This means better efficiency can be achieved by decomposing an arbitrary counter value into a number of double words plus single byte moves with a count value less than or equal to 3.

This certainly seems wrong on current hardware with ERMSB where rep movsb is at least as fast, or faster, than the movd or movq variants for large copies.

In general, that section (3.7.5) of the current guide contains a mix of reasonable and badly obsolete advice. This is common throughput the Intel manuals, since they are updated in an incremental fashion for each architecture (and purport to cover nearly two decades worth of architectures even in the current manual), and old sections are often not updated to replace or make conditional advice that doesn't apply to the current architecture.

They then go on to cover ERMSB explicitly in section 3.7.6.

I won't go over the remaining advice exhaustively, but I'll summarize the good parts in the "why use it" below.

Other important claims from the guide are that on Haswell, rep movsb has been enhanced to use 256-bit operations internally.

Technical Considerations

This is just a quick summary of the underlying advantages and disadvantages that the rep instructions have from an implementation standpoint.

Advantages for rep movs

1. When a rep movs instruction is issued, the CPU knows that an entire block of a known size is to be transferred. This can help it optimize the operation in a way that it cannot with discrete instructions, for example:

   • Avoiding the RFO request when it knows the entire cache line will be overwritten.
   • Issuing prefetch requests immediately and exactly. Hardware prefetching does a good job at detecting memcpy-like patterns, but it still takes a couple of reads to kick in and will "over-prefetch" many cache lines beyond the end of the copied region. rep movsb knows exactly the region size and can prefetch exactly.

2. Apparently, there is no guarantee of ordering among the stores within³ a single rep movs which can help simplify coherency traffic and simply other aspects of the block move, versus simple mov instructions which have to obey rather strict memory ordering⁴.

3. In principle, the rep movs instruction could take advantage of various architectural tricks that aren't exposed in the ISA. For example, architectures may have wider internal data paths that the ISA exposes⁵ and rep movs could use that internally.

Disadvantages

1. rep movsb must implement a specific semantic which may be stronger than the underlying software requirement. In particular, memcpy forbids overlapping regions, and so may ignore that possibility, but rep movsb allows them and must produce the expected result. On current implementations mostly affects to startup overhead, but probably not to large-block throughput. Similarly, rep movsb must support byte-granular copies even if you are actually using it to copy large blocks which are a multiple of some large power of 2.

2. The software may have information about alignment, copy size and possible aliasing that cannot be communicated to the hardware if using rep movsb. Compilers can often determine the alignment of memory blocks⁶ and so can avoid much of the startup work that rep movs must do on every invocation.

Test Results

Here are test results for many different copy methods from tinymembench on my i7-6700HQ at 2.6 GHz (too bad I have the identical CPU so we aren't getting a new data point...):

 C copy backwards                                     :   8284.8 MB/s (0.3%)  C copy backwards (32 byte blocks)                    :   8273.9 MB/s (0.4%)  C copy backwards (64 byte blocks)                    :   8321.9 MB/s (0.8%)  C copy                                               :   8863.1 MB/s (0.3%)  C copy prefetched (32 bytes step)                    :   8900.8 MB/s (0.3%)  C copy prefetched (64 bytes step)                    :   8817.5 MB/s (0.5%)  C 2-pass copy                                        :   6492.3 MB/s (0.3%)  C 2-pass copy prefetched (32 bytes step)             :   6516.0 MB/s (2.4%)  C 2-pass copy prefetched (64 bytes step)             :   6520.5 MB/s (1.2%)  ---  standard memcpy                                      :  12169.8 MB/s (3.4%)  standard memset                                      :  23479.9 MB/s (4.2%)  ---  MOVSB copy                                           :  10197.7 MB/s (1.6%)  MOVSD copy                                           :  10177.6 MB/s (1.6%)  SSE2 copy                                            :   8973.3 MB/s (2.5%)  SSE2 nontemporal copy                                :  12924.0 MB/s (1.7%)  SSE2 copy prefetched (32 bytes step)                 :   9014.2 MB/s (2.7%)  SSE2 copy prefetched (64 bytes step)                 :   8964.5 MB/s (2.3%)  SSE2 nontemporal copy prefetched (32 bytes step)     :  11777.2 MB/s (5.6%)  SSE2 nontemporal copy prefetched (64 bytes step)     :  11826.8 MB/s (3.2%)  SSE2 2-pass copy                                     :   7529.5 MB/s (1.8%)  SSE2 2-pass copy prefetched (32 bytes step)          :   7122.5 MB/s (1.0%)  SSE2 2-pass copy prefetched (64 bytes step)          :   7214.9 MB/s (1.4%)  SSE2 2-pass nontemporal copy                         :   4987.0 MB/s 

Some key takeaways:

• The rep movs methods are faster than all the other methods which aren't "non-temporal"⁷, and considerably faster than the "C" approaches which copy 8 bytes at a time.
• The "non-temporal" methods are faster, by up to about 26% than the rep movs ones - but that's a much smaller delta than the one you reported (26 GB/s vs 15 GB/s = ~73%).
• If you are not using non-temporal stores, using 8-byte copies from C is pretty much just as good as 128-bit wide SSE load/stores. That's because a good copy loop can generate enough memory pressure to saturate the bandwidth (e.g., 2.6 GHz * 1 store/cycle * 8 bytes = 26 GB/s for stores).
• There are no explicit 256-bit algorithms in tinymembench (except probably the "standard" memcpy) but it probably doesn't matter due to the above note.
• The increased throughput of the non-temporal store approaches over the temporal ones is about 1.45x, which is very close to the 1.5x you would expect if NT eliminates 1 out of 3 transfers (i.e., 1 read, 1 write for NT vs 2 reads, 1 write). The rep movs approaches lie in the middle.
• The combination of fairly low memory latency and modest 2-channel bandwidth means this particular chip happens to be able to saturate its memory bandwidth from a single-thread, which changes the behavior dramatically.
• rep movsd seems to use the same magic as rep movsb on this chip. That's interesting because ERMSB only explicitly targets movsb and earlier tests on earlier archs with ERMSB show movsb performing much faster than movsd. This is mostly academic since movsb is more general than movsd anyway.

Haswell

Looking at the Haswell results kindly provided by iwillnotexist in the comments, we see the same general trends (most relevant results extracted):

 C copy                                               :   6777.8 MB/s (0.4%)  standard memcpy                                      :  10487.3 MB/s (0.5%)  MOVSB copy                                           :   9393.9 MB/s (0.2%)  MOVSD copy                                           :   9155.0 MB/s (1.6%)  SSE2 copy                                            :   6780.5 MB/s (0.4%)  SSE2 nontemporal copy                                :  10688.2 MB/s (0.3%) 

The rep movsb approach is still slower than the non-temporal memcpy, but only by about 14% here (compared to ~26% in the Skylake test). The advantage of the NT techniques above their temporal cousins is now ~57%, even a bit more than the theoretical benefit of the bandwidth reduction.

When should you use rep movs?

Finally a stab at your actual question: when or why should you use it? It draw on the above and introduces a few new ideas. Unfortunately there is no simple answer: you'll have to trade off various factors, including some which you probably can't even know exactly, such as future developments.

A note that the alternative to rep movsb may be the optimized libc memcpy (including copies inlined by the compiler), or it may be a hand-rolled memcpy version. Some of the benefits below apply only in comparison to one or the other of these alternatives (e.g., "simplicity" helps against a hand-rolled version, but not against built-in memcpy), but some apply to both.

Restrictions on available instructions

In some environments there is a restriction on certain instructions or using certain registers. For example, in the Linux kernel, use of SSE/AVX or FP registers is generally disallowed. Therefore most of the optimized memcpy variants cannot be used as they rely on SSE or AVX registers, and a plain 64-bit mov-based copy is used on x86. For these platforms, using rep movsb allows most of the performance of an optimized memcpy without breaking the restriction on SIMD code.

A more general example might be code that has to target many generations of hardware, and which doesn't use hardware-specific dispatching (e.g., using cpuid). Here you might be forced to use only older instruction sets, which rules out any AVX, etc. rep movsb might be a good approach here since it allows "hidden" access to wider loads and stores without using new instructions. If you target pre-ERMSB hardware you'd have to see if rep movsb performance is acceptable there, though...

Future Proofing

A nice aspect of rep movsb is that it can, in theory take advantage of architectural improvement on future architectures, without source changes, that explicit moves cannot. For example, when 256-bit data paths were introduced, rep movsb was able to take advantage of them (as claimed by Intel) without any changes needed to the software. Software using 128-bit moves (which was optimal prior to Haswell) would have to be modified and recompiled.

So it is both a software maintenance benefit (no need to change source) and a benefit for existing binaries (no need to deploy new binaries to take advantage of the improvement).

How important this is depends on your maintenance model (e.g., how often new binaries are deployed in practice) and a very difficult to make judgement of how fast these instructions are likely to be in the future. At least Intel is kind of guiding uses in this direction though, by committing to at least reasonable performance in the future (15.3.3.6):

REP MOVSB and REP STOSB will continue to perform reasonably well on future processors.

Overlapping with subsequent work

This benefit won't show up in a plain memcpy benchmark of course, which by definition doesn't have subsequent work to overlap, so the magnitude of the benefit would have to be carefully measured in a real-world scenario. Taking maximum advantage might require re-organization of the code surrounding the memcpy.

This benefit is pointed out by Intel in their optimization manual (section 11.16.3.4) and in their words:

When the count is known to be at least a thousand byte or more, using enhanced REP MOVSB/STOSB can provide another advantage to amortize the cost of the non-consuming code. The heuristic can be understood using a value of Cnt = 4096 and memset() as example:

• A 256-bit SIMD implementation of memset() will need to issue/execute retire 128 instances of 32- byte store operation with VMOVDQA, before the non-consuming instruction sequences can make their way to retirement.

• An instance of enhanced REP STOSB with ECX= 4096 is decoded as a long micro-op flow provided by hardware, but retires as one instruction. There are many store_data operation that must complete before the result of memset() can be consumed. Because the completion of store data operation is de-coupled from program-order retirement, a substantial part of the non-consuming code stream can process through the issue/execute and retirement, essentially cost-free if the non-consuming sequence does not compete for store buffer resources.

So Intel is saying that after all some uops the code after rep movsb has issued, but while lots of stores are still in flight and the rep movsb as a whole hasn't retired yet, uops from following instructions can make more progress through the out-of-order machinery than they could if that code came after a copy loop.

The uops from an explicit load and store loop all have to actually retire separately in program order. That has to happen to make room in the ROB for following uops.

There doesn't seem to be much detailed information about how very long microcoded instruction like rep movsb work, exactly. We don't know exactly how micro-code branches request a different stream of uops from the microcode sequencer, or how the uops retire. If the individual uops don't have to retire separately, perhaps the whole instruction only takes up one slot in the ROB?

When the front-end that feeds the OoO machinery sees a rep movsb instruction in the uop cache, it activates the Microcode Sequencer ROM (MS-ROM) to send microcode uops into the queue that feeds the issue/rename stage. It's probably not possible for any other uops to mix in with that and issue/execute⁸ while rep movsb is still issuing, but subsequent instructions can be fetched/decoded and issue right after the last rep movsb uop does, while some of the copy hasn't executed yet. This is only useful if at least some of your subsequent code doesn't depend on the result of the memcpy (which isn't unusual).

Now, the size of this benefit is limited: at most you can execute N instructions (uops actually) beyond the slow rep movsb instruction, at which point you'll stall, where N is the ROB size. With current ROB sizes of ~200 (192 on Haswell, 224 on Skylake), that's a maximum benefit of ~200 cycles of free work for subsequent code with an IPC of 1. In 200 cycles you can copy somewhere around 800 bytes at 10 GB/s, so for copies of that size you may get free work close to the cost of the copy (in a way making the copy free).

As copy sizes get much larger, however, the relative importance of this diminishes rapidly (e.g., if you are copying 80 KB instead, the free work is only 1% of the copy cost). Still, it is quite interesting for modest-sized copies.

Copy loops don't totally block subsequent instructions from executing, either. Intel does not go into detail on the size of the benefit, or on what kind of copies or surrounding code there is most benefit. (Hot or cold destination or source, high ILP or low ILP high-latency code after).

Code Size

The executed code size (a few bytes) is microscopic compared to a typical optimized memcpy routine. If performance is at all limited by i-cache (including uop cache) misses, the reduced code size might be of benefit.

Again, we can bound the magnitude of this benefit based on the size of the copy. I won't actually work it out numerically, but the intuition is that reducing the dynamic code size by B bytes can save at most C * B cache-misses, for some constant C. Every call to memcpy incurs the cache miss cost (or benefit) once, but the advantage of higher throughput scales with the number of bytes copied. So for large transfers, higher throughput will dominate the cache effects.

Again, this is not something that will show up in a plain benchmark, where the entire loop will no doubt fit in the uop cache. You'll need a real-world, in-place test to evaluate this effect.

Architecture Specific Optimization

You reported that on your hardware, rep movsb was considerably slower than the platform memcpy. However, even here there are reports of the opposite result on earlier hardware (like Ivy Bridge).

That's entirely plausible, since it seems that the string move operations get love periodically - but not every generation, so it may well be faster or at least tied (at which point it may win based on other advantages) on the architectures where it has been brought up to date, only to fall behind in subsequent hardware.

Quoting Andy Glew, who should know a thing or two about this after implementing these on the P6:

the big weakness of doing fast strings in microcode was [...] the microcode fell out of tune with every generation, getting slower and slower until somebody got around to fixing it. Just like a library men copy falls out of tune. I suppose that it is possible that one of the missed opportunities was to use 128-bit loads and stores when they became available, and so on.

In that case, it can be seen as just another "platform specific" optimization to apply in the typical every-trick-in-the-book memcpy routines you find in standard libraries and JIT compilers: but only for use on architectures where it is better. For JIT or AOT-compiled stuff this is easy, but for statically compiled binaries this does require platform specific dispatch, but that often already exists (sometimes implemented at link time), or the mtune argument can be used to make a static decision.

Simplicity

Even on Skylake, where it seems like it has fallen behind the absolute fastest non-temporal techniques, it is still faster than most approaches and is very simple. This means less time in validation, fewer mystery bugs, less time tuning and updating a monster memcpy implementation (or, conversely, less dependency on the whims of the standard library implementors if you rely on that).

Latency Bound Platforms

Memory throughput bound algorithms⁹ can actually be operating in two main overall regimes: DRAM bandwidth bound or concurrency/latency bound.

The first mode is the one that you are probably familiar with: the DRAM subsystem has a certain theoretic bandwidth that you can calculate pretty easily based on the number of channels, data rate/width and frequency. For example, my DDR4-2133 system with 2 channels has a max bandwidth of 2.133 * 8 * 2 = 34.1 GB/s, same as reported on ARK.

You won't sustain more than that rate from DRAM (and usually somewhat less due to various inefficiencies) added across all cores on the socket (i.e., it is a global limit for single-socket systems).

The other limit is imposed by how many concurrent requests a core can actually issue to the memory subsystem. Imagine if a core could only have 1 request in progress at once, for a 64-byte cache line - when the request completed, you could issue another. Assume also very fast 50ns memory latency. Then despite the large 34.1 GB/s DRAM bandwidth, you'd actually only get 64 bytes / 50 ns = 1.28 GB/s, or less than 4% of the max bandwidth.

In practice, cores can issue more than one request at a time, but not an unlimited number. It is usually understood that there are only 10 line fill buffers per core between the L1 and the rest of the memory hierarchy, and perhaps 16 or so fill buffers between L2 and DRAM. Prefetching competes for the same resources, but at least helps reduce the effective latency. For more details look at any of the great posts Dr. Bandwidth has written on the topic, mostly on the Intel forums.

Still, most recent CPUs are limited by this factor, not the RAM bandwidth. Typically they achieve 12 - 20 GB/s per core, while the RAM bandwidth may be 50+ GB/s (on a 4 channel system). Only some recent gen 2-channel "client" cores, which seem to have a better uncore, perhaps more line buffers can hit the DRAM limit on a single core, and our Skylake chips seem to be one of them.

Now of course, there is a reason Intel designs systems with 50 GB/s DRAM bandwidth, while only being to sustain < 20 GB/s per core due to concurrency limits: the former limit is socket-wide and the latter is per core. So each core on an 8 core system can push 20 GB/s worth of requests, at which point they will be DRAM limited again.

Why I am going on and on about this? Because the best memcpy implementation often depends on which regime you are operating in. Once you are DRAM BW limited (as our chips apparently are, but most aren't on a single core), using non-temporal writes becomes very important since it saves the read-for-ownership that normally wastes 1/3 of your bandwidth. You see that exactly in the test results above: the memcpy implementations that don't use NT stores lose 1/3 of their bandwidth.

If you are concurrency limited, however, the situation equalizes and sometimes reverses, however. You have DRAM bandwidth to spare, so NT stores don't help and they can even hurt since they may increase the latency since the handoff time for the line buffer may be longer than a scenario where prefetch brings the RFO line into LLC (or even L2) and then the store completes in LLC for an effective lower latency. Finally, server uncores tend to have much slower NT stores than client ones (and high bandwidth), which accentuates this effect.

So on other platforms you might find that NT stores are less useful (at least when you care about single-threaded performance) and perhaps rep movsb wins where (if it gets the best of both worlds).

Really, this last item is a call for most testing. I know that NT stores lose their apparent advantage for single-threaded tests on most archs (including current server archs), but I don't know how rep movsb will perform relatively...

References

Other good sources of info not integrated in the above.

comp.arch investigation of rep movsb versus alternatives. Lots of good notes about branch prediction, and an implementation of the approach I've often suggested for small blocks: using overlapping first and/or last read/writes rather than trying to write only exactly the required number of bytes (for example, implementing all copies from 9 to 16 bytes as two 8-byte copies which might overlap in up to 7 bytes).

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¹ Presumably the intention is to restrict it to cases where, for example, code-size is very important.

² See Section 3.7.5: REP Prefix and Data Movement.

³ It is key to note this applies only for the various stores within the single instruction itself: once complete, the block of stores still appear ordered with respect to prior and subsequent stores. So code can see stores from the rep movs out of order with respect to each other but not with respect to prior or subsequent stores (and it's the latter guarantee you usually need). It will only be a problem if you use the end of the copy destination as a synchronization flag, instead of a separate store.

⁴ Note that non-temporal discrete stores also avoid most of the ordering requirements, although in practice rep movs has even more freedom since there are still some ordering constraints on WC/NT stores.

⁵ This is was common in the latter part of the 32-bit era, where many chips had 64-bit data paths (e.g, to support FPUs which had support for the 64-bit double type). Today, "neutered" chips such as the Pentium or Celeron brands have AVX disabled, but presumably rep movs microcode can still use 256b loads/stores.

⁶ E.g., due to language alignment rules, alignment attributes or operators, aliasing rules or other information determined at compile time. In the case of alignment, even if the exact alignment can't be determined, they may at least be able to hoist alignment checks out of loops or otherwise eliminate redundant checks.

⁷ I'm making the assumption that "standard" memcpy is choosing a non-temporal approach, which is highly likely for this size of buffer.

⁸ That isn't necessarily obvious, since it could be the case that the uop stream that is generated by the rep movsb simply monopolizes dispatch and then it would look very much like the explicit mov case. It seems that it doesn't work like that however - uops from subsequent instructions can mingle with uops from the microcoded rep movsb.

⁹ I.e., those which can issue a large number of independent memory requests and hence saturate the available DRAM-to-core bandwidth, of which memcpy would be a poster child (and as apposed to purely latency bound loads such as pointer chasing).