I have a file as show below
1.2.3.4.ask
sanma.nam.sam
c.d.b.test
I want to remove the last field from each line, the delimiter is .
and the number of fields are not constant.
Can anybody help me with an awk
or sed
to find out the solution. I can't use perl
here.
Both these sed
and awk
solutions work independent of the number of fields.
Using sed
:
$ sed -r 's/(.*)\..*/\1/' file
1.2.3.4
sanma.nam
c.d.b
Note: -r
is the flag for extended regexp, it could be -E
so check with man sed
. If your version of sed
doesn't have a flag for this then just escape the brackets:
sed 's/\(.*\)\..*/\1/' file
1.2.3.4
sanma.nam
c.d.b
The sed
solution is doing a greedy match up to the last .
and capturing everything before it, it replaces the whole line with only the matched part (n-1
fields). Use the -i
option if you want the changes to be stored back to the files.
Using awk
:
$ awk 'BEGIN{FS=OFS="."}{NF--; print}' file
1.2.3.4
sanma.nam
c.d.b
The awk
solution just simply prints n-1
fields, to store the changes back to the file use redirection:
$ awk 'BEGIN{FS=OFS="."}{NF--; print}' file > tmp && mv tmp file
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