Capitalize the first letter of every word in a filename or directory in Shell

Question

I'm trying to write a shell command where I can specify a directory, and then every file and directory inside will have the first letter of every word capitalized. So

/doCumenTS/tesT.txt

should change to

/DoCumenTS/TesT.txt

I'm thinking it should start like

for i in directory do
tr something_goes_here
done

The problem I can't figure out is how to only do the first letter. I've made a script that uppercase the whole file name, but I can't figure out how to only get the first letter of every word.

Thanks!

Answer 1

Source="ONE TWO THREE FOUR"
Target="One Two Three Four"

Solution is below:

Target=`echo $Source | tr [A-Z] [a-z] | sed -e 's/^./\U&/g; s/ ./\U&/g'`
echo $Target

One Two Three Four

Taken from here: http://souravgulati.webs.com/apps/forums/topics/show/8584862-shell-script-capitalize-first-letter-of-every-word-of-a-line-

Answer 2

Using GNU Sed

You can do this quite easily with GNU sed. For example:

$ echo '/doCumenTS/tesT.txt' | sed 's!/.!\U&!g'
/DoCumenTS/TesT.txt

Limitations

Note that the \U escape is a GNU sed extension. The manual says:

Finally, as a GNU 'sed' extension, you can include a special sequence made of a backslash and one of the letters 'L', 'l', 'U', 'u', or 'E'.

`\U'
     Turn the replacement to uppercase until a `\L' or `\E' is found