Use output of bash command (with pipe) as a parameter for another command

Question

I'm looking for a way to use the ouput of a command (say command1) as an argument for another command (say command2).

I encountered this problem when trying to grep the output of who command but using a pattern given by another set of command (actually tty piped to sed).

Context:

If tty displays:

/dev/pts/5

And who displays:

root     pts/4        2012-01-15 16:01 (xxxx)
root     pts/5        2012-02-25 10:02 (yyyy)
root     pts/2        2012-03-09 12:03 (zzzz)

Goal:

I want only the line(s) regarding "pts/5" So I piped tty to sed as follows:

$ tty | sed 's/\/dev\///'
pts/5

Test:

The attempted following command doesn't work:

$ who | grep $(echo $(tty) | sed 's/\/dev\///')"

Possible solution:

I've found out that the following works just fine:

$ eval "who | grep $(echo $(tty) | sed 's/\/dev\///')"

But I'm sure the use of eval could be avoided.

As a final side node: I've noticed that the "-m" argument to who gives me exactly what I want (get only the line of who that is linked to current user). But I'm still curious on how I could make this combination of pipes and command nesting to work...

Answer 1

One usually uses xargs to make the output of one command an option to another command. For example:

$ cat command1
#!/bin/sh

echo "one"
echo "two"
echo "three"

$ cat command2
#!/bin/sh

printf '1 = %s\n' "$1"

$ ./command1 | xargs -n 1 ./command2
1 = one
1 = two
1 = three
$ 

But ... while that was your question, it's not what you really want to know.

If you don't mind storing your tty in a variable, you can use bash variable mangling to do your substitution:

$ tty=`tty`; who | grep -w "${tty#/dev/}"
ghoti            pts/198  Mar  8 17:01 (:0.0)

(You want the -w because if you're on pts/6 you shouldn't see pts/60's logins.)

You're limited to doing this in a variable, because if you try to put the tty command into a pipe, it thinks that it's not running associated with a terminal anymore.

$ true | echo `tty | sed 's:/dev/::'`
not a tty
$ 

Note that nothing in this answer so far is specific to bash. Since you're using bash, another way around this problem is to use process substitution. For example, while this does not work:

$ who | grep "$(tty | sed 's:/dev/::')"

This does:

$ grep $(tty | sed 's:/dev/::') < <(who)

Answer 2

You can do this without resorting to sed with the help of Bash variable mangling, although as @ruakh points out this won't work in the single line version (without the semicolon separating the commands). I'm leaving this first approach up because I think it's interesting that it doesn't work in a single line:

TTY=$(tty); who | grep "${TTY#/dev/}"

This first puts the output of tty into a variable, then erases the leading /dev/ on grep's use of it. But without the semicolon TTY is not in the environment by the moment bash does the variable expansion/mangling for grep.

Here's a version that does work because it spawns a subshell with the already modified environment (that has TTY):

TTY=$(tty) WHOLINE=$(who | grep "${TTY#/dev/}")

The result is left in $WHOLINE.