How to preserve double quotes in $@ in a shell script?

Question

Let's say I have a really simple shell script 'foo':

  #!/bin/sh
  echo $@

If I invoke it like so:

  foo 1 2 3

It happily prints:

  1 2 3

However, let's say one of my arguments is double-quote enclosed and contains whitespace:

  foo 1 "this arg has whitespace" 3

foo happily prints:

  1 this arg has whitespace 3

The double-quotes have been stripped! I know shell thinks its doing me a favor, but... I would like to get at the original version of the arguments, unmolested by shell's interpretation. Is there any way to do so?

Answer 1

First, you probably want quoted version of $@, i.e. "$@". To feel the difference, try putting more than one space inside the string.

Second, quotes are element of shell's syntax -- it doesn't do you a favor. To preserve them, you need to escape them. Examples:

foo 1 "\"this arg has whitespace\"" 3

foo 1 '"this arg has whitespace"' 3

Answer 2

Double quote $@:

#!/bin/sh
for ARG in "$@"
do
    echo $ARG
done

Then:

foo 1 "this arg has whitespace" 3

will give you:

1
this arg has whitespace
3