Bash, grep between two lines with specified string

Question

Example:

a43 test1 abc cvb bnm test2 kfo 

I need all lines between test1 and test2. Normal grep does not work in this case. Do you have any propositions?

Answer 1

Print from test1 to test2 (Trigger lines included)

awk '/test1/{f=1} /test2/{f=0;print} f' awk '/test1/{f=1} f; /test2/{f=0}'  awk '/test1/,/test2/' 

test1 abc cvb bnm test2 

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Prints data between test1 to test2 (Trigger lines excluded)

awk '/test1/{f=1;next} /test2/{f=0} f'  awk '/test2/{f=0} f; /test1/{f=1}'  

abc cvb bnm 

Answer 2

You could use sed:

sed -n '/test1/,/test2/p' filename 

In order to exclude the lines containing test1 and test2, say:

sed -n '/test1/,/test2/{/test1/b;/test2/b;p}' filename