Menu
I thought it may be [.\n]+ but that doesn't seem to work?
944
By default in most regex engines, . doesn't match newline characters, so the matching stops at the end of each logical line. If you want . to match really everything, including newlines, you need to enable "dot-matches-all" mode in your regex engine of choice (for example, add re. DOTALL flag in Python, or /s in PCRE.
String regex = "\\."; Notice that the regular expression String contains two backslashes after each other, and then a . . The reason is, that first the Java compiler interprets the two \\ characters as an escaped Java String character. After the Java compiler is done, only one \ is left, as \\ means the character \ .
Line terminators A carriage-return character followed immediately by a newline character ("\r\n"), A standalone carriage-return character ('\r'), A next-line character ('\u0085'), A line-separator character ('\u2028'), or. A paragraph-separator character ('\u2029).
\\. matches the literal character . . the first backslash is interpreted as an escape character by the Emacs string reader, which combined with the second backslash, inserts a literal backslash character into the string being read. the regular expression engine receives the string \.
The dot cannot be used inside character classes.
See the option Pattern.DOTALL.
Pattern.DOTALLEnables dotall mode. In dotall mode, the expression.matches any character, including a line terminator. By default this expression does not match line terminators. Dotall mode can also be enabled via the embedded flag expression(?s). (The s is a mnemonic for "single-line" mode, which is what this is called in Perl.)
If you need it on just a portion of the regular expression, you use e.g. [\s\S].
97
Edit: While my original answer is technically correct, as ThorSummoner pointed out, it can be done more efficiently like so
[\s\S]as compared to (.|\n) or (.|\n|\r)
43
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
