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I am trying to parse an XML file into smaller XML files and place them into folders. The folders get generated based on some of the elements in XML.
How do I generating folders in XSLT? I was able to generate files using xsl:result-document, but so far I had no luck with finding how to generate folders.
958
You don't need to create folders specifically, just supply full desired path like folder1/doc1.xml. For example:
<?xml version="1.0" encoding="UTF-8"?>
<tests>
<testrun run="test1">
<test name="foo" pass="true" />
<test name="bar" pass="true" />
<test name="baz" pass="true" />
</testrun>
<testrun run="test2">
<test name="foo" pass="true" />
<test name="bar" pass="false" />
<test name="baz" pass="false" />
</testrun>
<testrun run="test3">
<test name="foo" pass="false" />
<test name="bar" pass="true" />
<test name="baz" pass="false" />
</testrun>
</tests>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output method="text"/>
<xsl:output method="html" indent="yes" name="html"/>
<xsl:template match="/">
<xsl:for-each select="//testrun">
<xsl:variable name="filename"
select="concat('output1/',@run,'.html')" />
<xsl:value-of select="$filename" /> <!-- Creating -->
<xsl:result-document href="{$filename}" format="html">
<html><body>
<xsl:value-of select="@run"/>
</body></html>
</xsl:result-document>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
It's probably implementation-dependent, but if you use Saxon then <xsl:result-document href="foo/bar/baz/sample.xml"/> will create the folders if they don't already exist.
23
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