xargs with multiple commands

Question

In the current directory, I'd like to print the filename and contents in it. I can print filenames or contents separately by

find . | grep "file_for_print" | xargs echo
find . | grep "file_for_print" | xargs cat

but what I want is printing them together like this:

file1
line1 inside file1
line2 inside file1
file2
line1 inside file2
line2 inside file2

I read xargs with multiple commands as argument and tried

find . | grep "file_for_print" | xargs -I % sh -c 'echo; cat;'

but doesn't work. I'm not familiar with xargs, so don't know what exactly "-I % sh -c" means. could anyone help me? thank you!

Answer 1

In this specific case, each command is executed for each individual file anyway, so there's no advantage in using xargs. You may just append -exec twice to your 'find':

find . -name "*file_for_print*" -exec echo {} \; -exec cat {} \;

In this case-print could be used instead of the first echo as pointed out by rici, but this example shows the ability to execute two arbitrary commands with a single find

Answer 2

find . | grep "file_for_print" | xargs -I % sh -c 'echo %; cat %;' (OP was missing %s)