Windows batch files: how to compare command line argument to an integer

Question

I am only very new to batch file programming and I have tried to find the solution online, but failed. My batch file calls a c program passing it's own command line arguments to the program then does subsequent steps which depend on the value of the fourth argument (which is an integer). I would like to do an extra step in my batch file if %4 is equal to 3. I have placed some echo test statements. But only the "testno" gets printed even if I enter 3 as my fourth argument.

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Batch file name: p2debug1234.bat

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Batch file code:

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@echo off
@setlocal 
p2task1 %1 %2 %3 %4
start mi_viewer %1
start mi_viewer %2
echo %4
echo 3
If ("%4"== "3") (echo testyes) Else (echo testno)
echo testif

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Command prompt snapshot:

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H:\ELEC4622\labs\data>p2debug1234 pens_rgb.bmp test.bmp 2 3

3
3
testno
testif

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Please help me make a valid comparison.

Best Regards, Julia

Answer 1

Change line:

If ("%4"== "3") (echo testyes) Else (echo testno)

to:

If "%4"=="3" (echo testyes) Else (echo testno)