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This is my string to obtain the position of TeamViewer (any version) service executable:
for /f "skip=1 delims=" %A in ('wmic path win32_service where "name like 'TeamViewer%'" get pathname') do set POSITION=%A
The problem is caused by wmic because it includes an empty line at the end of result (on Windows 7 command) and this is the output:
C:\Users\giovanni>for /f "skip=1 delims=" %A in ('wmic path win32_service where "name like 'TeamViewer%
'" get pathname') do set POSITION=%A
:\Users\giovanni>set POSITION="C:\Program Files\TeamViewer\Version8\TeamViewer_Service.exe"
:\Users\giovanni>set POSITION=
C:\Users\giovanni>echo %position%
ECHO enabled.
How I can get only the second line of the output with the correct position of the executable? (or skip the latest line, of course).
Thanks all in advance and have a nice day. Giovanni.
This is checktv.bat:
for /f "skip=1 delims=" %%A in ('wmic path win32_service where "name like 'TeamViewer%'" get pathname ^| findstr /r /v "^$"') do set POSITION=%%A
echo %POSITION%
236
Delete blank lines using the grep commandWhen used with the -v option, the grep command helps to remove blank lines. Below is a sample text file, sample. txt, with alternative non-empty and empty lines. To remove or delete all the empty lines in the sample text file, use the grep command as shown.
The d command in sed can be used to delete the empty lines in a file.
Like this:
for /f "skip=1 delims=" %A in (
'wmic path win32_service where "name like 'TeamViewer%'" get pathname ^| findstr /r /v "^$"'
) do set POSITION=%A
The findstr /r /v "^$" removes empty lines from the output.
60
wmic blah /value | find "=" >> wherever
output will be
field=value
no extra lines
tokenize from there, delim =
36
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