In a different question on Stack Overflow the answer included the following function:
julia> function nzcols(b::SubArray{T,2,P,Tuple{UnitRange{Int64},UnitRange{Int64}}}) where {T,P<:SparseMatrixCSC}
return collect(i+1-start(b.indexes[2])
for i in b.indexes[2]
if b.parent.colptr[i]<b.parent.colptr[i+1] &&
inrange(b.parent.rowval[nzrange(b.parent,i)],b.indexes[1]))
end
nzcols (generic function with 3 methods)
And it was parsed without error. When adding a new-line before where
clause for readability, an error suddenly appeared:
julia> function nzcols(b::SubArray{T,2,P,Tuple{UnitRange{Int64},UnitRange{Int64}}})
where {T,P<:SparseMatrixCSC}
return collect(i+1-start(b.indexes[2])
for i in b.indexes[2]
if b.parent.colptr[i]<b.parent.colptr[i+1] &&
inrange(b.parent.rowval[nzrange(b.parent,i)],b.indexes[1]))
end
ERROR: syntax: space before "{" not allowed in "where {"
Finally, when the parameter list parenthesis is moved to the where
line, the error disappears again:
julia> function nzcols(b::SubArray{T,2,P,Tuple{UnitRange{Int64},UnitRange{Int64}}}
) where {T,P<:SparseMatrixCSC}
return collect(i+1-start(b.indexes[2])
for i in b.indexes[2]
if b.parent.colptr[i]<b.parent.colptr[i+1] &&
inrange(b.parent.rowval[nzrange(b.parent,i)],b.indexes[1]))
end
nzcols (generic function with 3 methods)
What is the logic behind this syntax and should it be fixed?
This is similar to many other syntaxes in the language; if the parser has a "complete" syntax at the end of a line, it'll use that and move on.
julia> parse("begin; 1 \n+ 2; end")
quote # none, line 1:
1 # none, line 2:
+2
end
julia> parse("begin; 1 +\n 2; end")
quote # none, line 1:
1 + 2
end
Note that this means you can still break the where
clause onto a separate line, but the where
itself needs to be on the same line as the end of the function.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With