Let's assume I have this Dict
:
d=Dict("arg1"=>10,"arg2"=>20)
and a function like this:
function foo(;arg1,arg2,arg3,arg4,arg5)
#Do something
end
How can I call the function and pass the parameters in the Dict
d as parameters for the function?
I know I can do this:
foo(arg1=d["arg1"],arg2=d["arg2"])
But is there any way to automate this? I mean a way to figure out which arguments are defined in the Dict and pass it automatically to the function.
Passing Dictionary as kwargs “ kwargs ” stands for keyword arguments. It is used for passing advanced data objects like dictionaries to a function because in such functions one doesn't have a clue about the number of arguments, hence data passed is be dealt properly by adding “**” to the passing type.
Precede double stars ( ** ) to a dictionary argument to pass it to **kwargs parameter. Always place the **kwargs parameter at the end of the parameter list, or you'll get an error.
tl;dr. With CPython 2.7, using dict() to create dictionaries takes up to 6 times longer and involves more memory allocation operations than the literal syntax. Use {} to create dictionaries, especially if you are pre-populating them, unless the literal syntax does not work for your case.
Embrace keyword arguments in Python Consider using the * operator to require those arguments be specified as keyword arguments. And remember that you can accept arbitrary keyword arguments to the functions you define and pass arbitrary keyword arguments to the functions you call by using the ** operator.
Dictionaries with Symbol
keys can be directly splat
ted into the function call:
julia> d = Dict(:arg1 => 10, :arg2 => 12)
Dict{Symbol, Int64} with 2 entries:
:arg1 => 10
:arg2 => 12
julia> f(; arg1, arg2) = arg1 + arg2
f (generic function with 1 method)
julia> f(; d...)
22
Note the semicolon in the function call, which ensure that the elements in d
are interpreted as keyword arguments instead of positional arguments which just happen to be Pair
s.
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