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The default memory page size of the Linux kernel on x86 architecture was 4 KB, I wonder how was that calculated, and why ?
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4 KiB is widely popuplar page granularity in other architectures too. One could argue that this size comes from the division of a 32-bit virutal address into two 10-bit indexes in page directories/tables and the remaining 12 bits give the 4 KiB page size.
Page size is usually determined by the processor architecture. Traditionally, pages in a system had uniform size, such as 4,096 bytes. However, processor designs often allow two or more, sometimes simultaneous, page sizes due to its benefits. There are several points that can factor into choosing the best page size.
The default size of memory pages on most processors is 4KB, and although some processors use 8KB, 16KB, or 64KB as the default page size, 4KB pages are still the mainstream of the default memory page configuration of the operating system; in addition to the normal memory page size, different processors also contain ...
The default page size is fixed by what the MMU (memory management unit) of the CPU supports. In 32-bit protected mode x86 supports two kinds of pages:
Not all x86 processors support large pages. One needs to have a CPU with Page Size Extension (PSE) capabilities. This excludes pre-Pentium processors. Virtually all current-generation x86 CPUs implements it.
4 KiB is widely popuplar page granularity in other architectures too. One could argue that this size comes from the division of a 32-bit virutal address into two 10-bit indexes in page directories/tables and the remaining 12 bits give the 4 KiB page size.
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