When you have a struct implementing an interface, a pointer to that struct implements automatically that interface too. That's why you never have *SomeInterface
in the prototype of functions, as this wouldn't add anything to SomeInterface
, and you don't need such a type in variable declaration (see this related question).
An interface value isn't the value of the concrete struct (as it has a variable size, this wouldn't be possible), but it's a kind of pointer (to be more precise a pointer to the struct and a pointer to the type). Russ Cox describes it exactly here :
Interface values are represented as a two-word pair giving a pointer to information about the type stored in the interface and a pointer to the associated data.
This is why Interface
, and not *Interface
is the correct type to hold a pointer to a struct implementing Interface
.
So you must simply use
var pi Interface
This is perhaps what you meant:
package main
type Interface interface{}
type Struct struct{}
func main() {
var ps *Struct
var pi *Interface
pi = new(Interface)
*pi = ps
_, _ = pi, ps
}
Compiles OK. See also here.
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