In Go, when a variable is declared it is initialized with zero value as described in the specification.
Go does not have optional parameters nor does it support method overloading: Method dispatch is simplified if it doesn't need to do type matching as well.
A default argument is a value provided in a function declaration that is automatically assigned by the compiler if the calling function doesn't provide a value for the argument. In case any value is passed, the default value is overridden.
Use the variadic Function to Pass Optional Parameters in Go int) { fmt. Print(nums, " ") total := 0 for _, num := range nums { total += num } fmt. Println(total) } func main() { sum(1, 2) sum(1, 2, 3) nums := []int{1, 2, 3, 4} sum(nums...) }
NO,but there are some other options to implement default value. There are some good blog posts on the subject, but here are some specific examples.
// Both parameters are optional, use empty string for default value
func Concat1(a string, b int) string {
if a == "" {
a = "default-a"
}
if b == 0 {
b = 5
}
return fmt.Sprintf("%s%d", a, b)
}
// a is required, b is optional.
// Only the first value in b_optional will be used.
func Concat2(a string, b_optional ...int) string {
b := 5
if len(b_optional) > 0 {
b = b_optional[0]
}
return fmt.Sprintf("%s%d", a, b)
}
// A declarative default value syntax
// Empty values will be replaced with defaults
type Parameters struct {
A string `default:"default-a"` // this only works with strings
B string // default is 5
}
func Concat3(prm Parameters) string {
typ := reflect.TypeOf(prm)
if prm.A == "" {
f, _ := typ.FieldByName("A")
prm.A = f.Tag.Get("default")
}
if prm.B == 0 {
prm.B = 5
}
return fmt.Sprintf("%s%d", prm.A, prm.B)
}
func Concat4(args ...interface{}) string {
a := "default-a"
b := 5
for _, arg := range args {
switch t := arg.(type) {
case string:
a = t
case int:
b = t
default:
panic("Unknown argument")
}
}
return fmt.Sprintf("%s%d", a, b)
}
No, the powers that be at Google chose not to support that.
https://groups.google.com/forum/#!topic/golang-nuts/-5MCaivW0qQ
No, there is no way to specify defaults. I believer this is done on purpose to enhance readability, at the cost of a little more time (and, hopefully, thought) on the writer's end.
I think the proper approach to having a "default" is to have a new function which supplies that default to the more generic function. Having this, your code becomes clearer on your intent. For example:
func SaySomething(say string) {
// All the complicated bits involved in saying something
}
func SayHello() {
SaySomething("Hello")
}
With very little effort, I made a function that does a common thing and reused the generic function. You can see this in many libraries, fmt.Println
for example just adds a newline to what fmt.Print
would otherwise do. When reading someone's code, however, it is clear what they intend to do by the function they call. With default values, I won't know what is supposed to be happening without also going to the function to reference what the default value actually is.
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