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When does a process get SIGABRT (signal 6)?

Tags:

c++

sigabrt

What are the scenarios where a process gets a SIGABRT in C++? Does this signal always come from within the process or can this signal be sent from one process to another?

Is there a way to identify which process is sending this signal?

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Shree Avatar asked Aug 05 '10 09:08

Shree


People also ask

What does signal 6 caught mean?

Signal 6 ( SIGABRT ) = SIGABRT is commonly used by libc and other libraries to abort the program in case of critical errors. For example, glibc sends an SIGABRT in case of a detected double-free or other heap corruptions.

What is fatal signal 6 SIGABRT?

Fatal signal 6 SIGABRT it might means that your device hang at some point. Lost connection to device.

What causes SIGABRT?

SIGABRT errors are caused by your program aborting due to a fatal error. In C++, this is normally due to an assert statement in C++ not returning true, but some STL elements can generate this if they try to store too much memory.

What sends SIGABRT?

The SIGABRT signal is sent to a process to tell it to abort, i.e. to terminate. The signal is usually initiated by the process itself when it calls abort function of the C Standard Library, but it can be sent to the process from outside like any other signal.


2 Answers

abort() sends the calling process the SIGABRT signal, this is how abort() basically works.

abort() is usually called by library functions which detect an internal error or some seriously broken constraint. For example malloc() will call abort() if its internal structures are damaged by a heap overflow.

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Nordic Mainframe Avatar answered Sep 25 '22 02:09

Nordic Mainframe


SIGABRT is commonly used by libc and other libraries to abort the program in case of critical errors. For example, glibc sends an SIGABRT in case of a detected double-free or other heap corruptions.

Also, most assert implementations make use of SIGABRT in case of a failed assert.

Furthermore, SIGABRT can be sent from any other process like any other signal. Of course, the sending process needs to run as same user or root.

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IanH Avatar answered Sep 26 '22 02:09

IanH