I am trying to find out the version of Visual Studio that is used to compile the Python on my computer
It says
Python 2.6.2 (r262:71605, Apr 14 2009, 22:40:02) [MSC v.1500 32 bit (Intel)] on win32
What I do not understand is this MSC V.1500
designation. Does it mean it is compiled with Visual Studio 2005? I cannot find this information on http://python.org.
Visual Studio supports Python version 3.7. While it is possible to use Visual Studio to edit code written in other versions of Python, those versions are not officially supported and features such as IntelliSense and debugging might not work.
To quickly test Python support, launch Visual Studio, press Alt+I to open the Python Interactive window, and enter 2+2 . If you don't see the output of 4, recheck your steps.
Python Tools for Visual Studio is a completely free extension, developed and supported by Microsoft with contributions from the community.
Visual C++ version | _MSC_VER |
---|---|
Visual C++ 4.x | 1000 |
Visual C++ 5 | 1100 |
Visual C++ 6 | 1200 |
Visual C++ .NET | 1300 |
Visual C++ .NET 2003 | 1310 |
Visual C++ 2005 (8.0) | 1400 |
Visual C++ 2008 (9.0) | 1500 |
Visual C++ 2010 (10.0) | 1600 |
Visual C++ 2012 (11.0) | 1700 |
Visual C++ 2013 (12.0) | 1800 |
Visual C++ 2015 (14.0) | 1900 |
Visual C++ 2017 (15.0) | 1910 |
Visual C++ 2017 (15.3) | 1911 |
Visual C++ 2017 (15.5) | 1912 |
Visual C++ 2017 (15.6) | 1913 |
Visual C++ 2017 (15.7) | 1914 |
Visual C++ 2017 (15.8) | 1915 |
Visual C++ 2017 (15.9) | 1916 |
Visual C++ 2019 RTW (16.0) | 1920 |
Visual C++ 2019 (16.1) | 1921 |
Visual C++ 2019 (16.2) | 1922 |
Visual C++ 2019 (16.3) | 1923 |
Visual C++ 2019 (16.4) | 1924 |
Visual C++ 2019 (16.5) | 1925 |
Visual C++ 2019 (16.6) | 1926 |
Visual C++ 2019 (16.7) | 1927 |
Visual C++ 2019 (16.8) | 1928 |
Visual C++ 2019 (16.9) | 1928 |
Visual C++ 2019 (16.10) | 1929 |
Visual C++ 2019 (16.11) | 1929 |
Visual Studio 2022 RTW (17.0) | 1930 |
Source: the documentation for the _MSC_VER
predefined macro
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